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3 years ago

Solve |z| > (1/2)

Mathematics

1 answer:

Anestetic [448]3 years ago

8 0

Answer:

{ $z|z$ }U{ $z|z>\frac{1}{2}$ }

Step-by-step explanation:

Given the inequality $|z| > \frac{1}{2}$ you need to set up two posibilities:

FIRST POSIBILITY : $z>\frac{1}{2}$

SECOND POSIBILTY: $z$

Therefore, you got that:

$z\frac{1}{2}$

Knowing this, you can write the solution obtained in Set notation. This is:

Solution: { $z|z$ }U{ $z|z>\frac{1}{2}$ }

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Please help thanks!!!

lora16 [44]

$probablity \: of \: \: six = 29 : 150$

<h2>hope it helps you ❣❣ </h2>

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in fraction=29/150

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3 years ago

12. The function M(h) = 10e-0.173h can be used to find the number of milligrams M of morphine that is

vodomira [7]

Answer:

Part A; Initial dosage is 10 milligrams

Part B:

8.4113 milligrams after 1 hour

5.0057 milligrams after 4 hours.

Step-by-step explanation:

It is given M(h)= 10 $e^{-0.173h}$

Initial dosage is the 10 milligrams

After 1 hour, plug in h as 1

So, M(1)=10 $e^{-0.173*1}$

Simplify the right side

M(1)=10(0.84113)

M(1)= 8.4113 milligrams.

Now, after 4 hours

M(4)=10 $e^{-0.173*4}$

M(4)=10(0.50057)

M(4) =5.0057 milligrams

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3 years ago

What is the slope of the line shown in the graph?

faust18 [17]

Answer:

-1 over 2

Step-by-step explanation:

5 0

3 years ago

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Two vertical poles of length 10 and 12 feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the

Marat540 [252]

Answer:

$L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft$

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

$x^{2} +10^{2}=L_{1} ^{2} \\x^{2} + 100 = L_{1} ^{2}$

Take the square root of both sides

$\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\ \sqrt{x^{2}+100}= L_{1}$

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

$(17-x)^{2}+12^{2}=L_{2} ^{2} \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}$

Take the square root of both sides

$\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}} \\\sqrt{x^{2}-34x+433}=L_{2}$

Amount of cable used, L = L1 + L2

$L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}$

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3 years ago

-7a⁵· 6a write the product in simplest form ?

MariettaO [177]

Answer:

= -42a⁶

Step-by-step explanation:

-7a⁵. 6a = -7a⁵ × 6a

Therefore;

We multiply; -7 × 6 = -42

then; a⁵ × a = a⁶

Thus; we have -42 a⁶

Hence; -7a⁵ × 6a = -42 a⁶

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3 years ago

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