All categories

3 years ago

Solve |z| > (1/2)

Mathematics

1 answer:

Anestetic [448]3 years ago

8 0

Answer:

{ $z|z$ }U{ $z|z>\frac{1}{2}$ }

Step-by-step explanation:

Given the inequality $|z| > \frac{1}{2}$ you need to set up two posibilities:

FIRST POSIBILITY : $z>\frac{1}{2}$

SECOND POSIBILTY: $z$

Therefore, you got that:

$z\frac{1}{2}$

Knowing this, you can write the solution obtained in Set notation. This is:

Solution: { $z|z$ }U{ $z|z>\frac{1}{2}$ }

You might be interested in

ANSWER THESE 2 QUESTIONS ASAP PLEASE PLEASE PLEASEEEEEEE!

atroni [7]

Expanded form of 76 is 70+6
expanded form of 18 is 10+8

5 0

3 years ago

Can someone please help me

Firdavs [7]

Answer:

c. GOOD LUCKKKKK XD

Step-by-step explanation:

6 0

3 years ago

A shipping company needs to determine the number of Styrofoam packing peanuts that fit per square foot in a box that measures 20

Mumz [18]

1) We have 1300 packing peanuts, and 20 ft^2. Therefore, to find out how many packing peanuts there are per square foot, we divide the number of peanuts (1300) by the number of square feet (20 ft^2). This gives us 1300 / 20 = 65 packing peanuts per square foot.
2) We do not know the current volume of the box which fits the 1300 packing peanuts (all we know is its area). But it is reasonable to expect that if we increase the volume by 25%, the number of packing peanuts will also increase by 25%. This means we can fit 1300*(1.25) = 1625 peanuts in the larger box.
3) This will depend on how the box is larger. If its height remains the same, and its floor area increases to accommodate the greater volume, then the number of packing peanuts per square foot remains the same.
However, if the height of the box is different, then the number of packing peanuts per square foot will change, since the floor area will not increase by the same 25% any more.

3 0

4 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

Solve for x:<br> (x2−2x)2−8 = 7(x2−2x)

Marrrta [24]

Answer:

x1= -2

x2= 1

x3= 4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers