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3 years ago

Use the following figures to find the value of x.(any help would be appreciated)

Mathematics

1 answer:

Oliga [24]3 years ago

3 0

Answer:

x=9

Step-by-step explanation:

the two sides are equivalent so set equal to each other

x-6=1/3x

3x-18=x

3x-x=18

2x=18

x=9

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Desperate need for help!<br> Maths!<br> Will award brainliest!

stealth61 [152]

Step-by-step explanation:

fg(x) =

${(x - 4)}^{2} + 3(x - 4)$

${x}^{2} + 16 - 8x + 3x - 12$

${x}^{2} - 5x + 4$

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3 years ago

3+(-9)= oooooooooooooooooooooooo

Ad libitum [116K]

The answer is 3+(-9)= -6

7 0

3 years ago

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Use algebra to solve 3x+4 = 1/x<br> The exact solutions are x=<br> Х

skad [1K]

Answer:

Ignore the A before the ±, it wouldn't let me type it correctly.

$x=\frac{2±\sqrt{7} }{3}$

Step-by-step explanation:

3x + 4 = 1 ÷ x

3x + 4 - 4 = 1 ÷ x - 4

3x = 1 ÷ x - 4

$3x=\frac{1}{x} +\frac{x(-4)}{x}$

$3x=\frac{1+x(-4)}{x}$

$3x=\frac{1-4x}{x}$

$x(3x)=x(\frac{1-4x}{x})$

x · 3x = - 4x + 1

3x² = - 4x + 1

3x² - (- 4x + 1) = 0

3x² + 4x - 1 = 0

Ignore the A before the ±, it wouldn't let me type it correctly.

$x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

a = 3

b = 4

c = - 1

$x=\frac{-4±\sqrt{4^{2}-4((3)(-1)) } }{2(3)}$

$x=\frac{-4±\sqrt{16-4((3)(-1)) } }{2(3)}$

$x=\frac{-4±\sqrt{16+12 } }{2(3)}$

$x=\frac{-4±\sqrt{28 } }{2(3)}$

$x=\frac{-4±\sqrt{(2)(14) } }{2(3)}$

$x=\frac{-4±\sqrt{(2)(2)(7) } }{2(3)}$

$x=\frac{-4±\sqrt{2 } \sqrt{2}\sqrt{7} }{2(3)}$

$x=\frac{-4±2\sqrt{7} }{2(3)}$

$x=\frac{-4±2\sqrt{7} }{6}$

Two separate equations

$x=\frac{-4+2\sqrt{7} }{6}$

$x=\frac{2+\sqrt{7} }{3}$

$x=\frac{-4-2\sqrt{7} }{6}$

$x=\frac{2-\sqrt{7} }{3}$

7 0

3 years ago

Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s

Snezhnost [94]

Answer. First option: t > 6.25

Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25

5 0

4 years ago

Read 2 more answers

Please I need help

lianna [129]

Answer:

7 cases were missed

Step-by-step explanation:

40+20 = 70

70 points missed means they missed 7 total classes

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3 years ago

Use the following figures to find the value of x.(any help would be appreciated)​

Use the following figures to find the value of x.(any help would be appreciated)