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Paul [167]
3 years ago
10

A student solve this problem and said the answer is 9 pounds.

Mathematics
2 answers:
lukranit [14]3 years ago
7 0
Ethan bought 9.9 pounds of meat (2.2+3.6+4.1) I would say this is reasonable.
kondaur [170]3 years ago
7 0
The student is wrong because if you do 
2(1/5) + 3(3/5) + 4(1/10) it all equals up to 2.6
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Aleena expands 2xx+3-5(x-2) as 2x2+3-5x-10. Has she expanded it correctly? Please identify the mistakes and write the correct wa
Nimfa-mama [501]

The given expression is :

2xx+3-5(x-2)

We know that, x{\cdot}x=x^2

=2x^2+3-5(x-2)\\\\=2x^2+3+(-5)(x)+(-5)(-2)\\\\=2x^2+3-5x+10

Aleena expands 2xx+3-5(x-2) as 2x²+3-5x-10. She is mistaken because the sign before 10 should be +10 instead of -10. Hence, the correct expanded form is 2x²+3-5x+10. Hence, this is the required solution.

5 0
3 years ago
Y varies directly with x, and y = 5 when x = 4. What is the value of x when y = 8?
Tomtit [17]
As y varies directly with x, there is a proportionality constant. As x increases by that certain constant, y also increases. We equate:
y = kx
where k = proportionality constant.
Given the condition, y = 5 when x = 4, then we solve for k:
5 = k(4)
k = 5/4 or 1.25
When y = 8, then
8 = (5/4)(x)
x = 8/(5/4) = (8)(4/5) = 32/5 or 6.4 (ANSWER)
7 0
4 years ago
2(y-4)+5=3(y+2) for y​
brilliants [131]

2(y-4)+5=3(y+2)

multiply the first bracket by 2

(2)(y)=2y

(2)(-4)=-8

multiply the second bracket by 3

(3)(y)=3y

(3)(2)=6

2y-8+5=3y+6

2y-3=3y+6

move 3y to the other side

sign changes from +3y to -3y

2y-3y-3=3y-3y+6

-y-3=6

move -3 to the other side

-y-3+3=6+3

-y=9

multiply both sides by -1 to get +y

(-1)(-y)=9(-1)

Answer:

y=-9

3 0
3 years ago
Read 2 more answers
Jemima was arranging 400 packets of biscuits for a sale. She put 52 packets into a basket and displayed 25% of the remaining pac
stealth61 [152]

Answer:

87% of all the packets of biscuits Jemima displayed on the shelves.

Step-by-step explanation:

400-52=348

so, 348*25%

348*25/100

87

6 0
3 years ago
If x>2,then x2-x-6/x2-4=
statuscvo [17]
\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)
---------------------\\x^2-4=x^2-2^2=(x-2)(x+2)\\-------------------\\\\(*)=\frac{(x+2)(x-3)}{(x-2)(x+2)}=\frac{x-3}{x-2}


6 0
3 years ago
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