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dangina [55]
3 years ago
7

Bryan is setting in rows he has 50 black chairs and 60 white chairs

Mathematics
1 answer:
coldgirl [10]3 years ago
6 0
This is not written correctly. What is the question? What do I need to find out?
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Find the value of 4³
Gwar [14]

Answer:

64

Step-by-step explanation:

4^3 is the same as 4x4x4

4x4 = 16

16x4=64

so 4^3 is 64

4 0
1 year ago
Read 2 more answers
Can tell me the answer
bogdanovich [222]
The fraction 4/6 could represent the green

6 0
3 years ago
Read 2 more answers
Solve for for n. 10(n+4) = 63
storchak [24]

Answer:

n=23/10

Step-by-step explanation:

10(n+4)=63

n+4=63/10

n=63/10-4

n=23/10

decimal form: 2.3

3 0
3 years ago
Determine the average rate of change of f (x) = x² - 10x + 5 over the interval [-4, 4].<br> =<br> -
jeka57 [31]

Answer:

f ( x ) = ( x - 5 ) ² - 20

Step-by-step explanation:

1- Add the same value to both sides

f ( x ) = x ² - 10x + 5

2- Add 25 to the expression

f ( x ) + ? = x ² - 10x + ? + 5

3- Add 25 to the left-hand side

f ( x ) + ? = x ² - 10x + 25 + 5

4- Factor the expression

f ( x ) + 25 = x ² - 10x + 25 + 5

5- Move the constant to the right

f ( x ) + 25 = ( x - 5 ) ² + 5

6- Calculate

f ( x ) = ( x - 5) ² + 5 - 25

It will help me a lot if you count me as brainlist anyways good luck!

8 0
2 years ago
Help me please, need this done now.
Nikolay [14]

simplifying \frac{\sqrt{4}}{\sqrt[3]{4}} we get 4^{\frac{1}{6}}

Option B is correct.

Step-by-step explanation:

We need to simplify: \frac{\sqrt{4}}{\sqrt[3]{4}}

Solving:

\frac{\sqrt{4}}{\sqrt[3]{4}}

We know that √ = 1/2 and ∛=1/3

\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}

So, simplifying \frac{\sqrt{4}}{\sqrt[3]{4}} we get 4^{\frac{1}{6}}

Option B is correct.

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

6 0
3 years ago
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