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4 years ago

Bryan is setting in rows he has 50 black chairs and 60 white chairs

Mathematics

1 answer:

coldgirl [10]4 years ago

6 0

This is not written correctly. What is the question? What do I need to find out?

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Graph - 9x + 6y = 18 using linear standard form

postnew [5]

Answer:

The graph is attached Below and the plotting is given below.

Step-by-step explanation:

Given:

-9x + 6y = 18

Solution:

To draw a line on a graph the required minimum two points but here we will have three points as point A, point B, and point C.

For point A

Put x = -4 in the given equation we get

-9×-4 + 6y = 18

6y = 18-36

∴ $y=\frac{-18}{3}\\ \\y=-3$

∴ Point A ≡ ( -4, -3 ).

For point B

Put x = -2 in the given equation we get

-9×-2 + 6y = 18

6y = 18 - 18

6y = 0

∴ $y=\frac{0}{3}\\ \\y=0$

∴ Point B ≡ ( -2, 0 ).

For point C

Put x = 0 in the given equation we get

-9×0 + 6y = 18

6y = 18

∴ $y=\frac{18}{3}\\ \\y=3$

∴ Point C ≡ ( 0, 3 ).

Now we have Point A ,B and C join it and you will have Line.

3 0

4 years ago

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$