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Anton [14]
3 years ago
8

Perform the indicated operation. (2x + y)(3x^2 + y)

Mathematics
1 answer:
alekssr [168]3 years ago
4 0

Answer:

(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)

Step-by-step explanation:

The given expression is (2x+y)(3x^2+y).

We expand the parenthesis using the distributive property to obtain;

(2x+y)(3x^2+y)=2x(3x^2+y)+y(3x^2+y)

We expand further to get;

(2x+y)(3x^2+y)=6x^3+2xy+3x^2y+y^2)

This gives us;

(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)

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