Question

Perform the indicated operation. (2x + y)(3x^2 + y)

Answer 1

Answer:

$(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)$

Step-by-step explanation:

The given expression is $(2x+y)(3x^2+y)$.

We expand the parenthesis using the distributive property to obtain;

$(2x+y)(3x^2+y)=2x(3x^2+y)+y(3x^2+y)$

We expand further to get;

$(2x+y)(3x^2+y)=6x^3+2xy+3x^2y+y^2)$

This gives us;

$(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)$