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3 years ago

Perform the indicated operation. (2x + y)(3x^2 + y)

Mathematics

1 answer:

alekssr [168]3 years ago

4 0

Answer:

$(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)$

Step-by-step explanation:

The given expression is $(2x+y)(3x^2+y)$ .

We expand the parenthesis using the distributive property to obtain;

$(2x+y)(3x^2+y)=2x(3x^2+y)+y(3x^2+y)$

We expand further to get;

$(2x+y)(3x^2+y)=6x^3+2xy+3x^2y+y^2)$

This gives us;

$(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)$

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3 years ago

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3 years ago

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olga55 [171]

Answer:

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Step-by-step explanation:

Sodas: s

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3 years ago

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3 years ago

4(x-3)=2(3x+1) 2 solve for x

Katarina [22]

Hi there!

Th' Eqn. is :-

4 (x - 3) = 2 (3x + 1)

=> 4x - 12 = 2 (3x + 1)

=> 4x - 12 = 6x + 2

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=> 4x - 6x = 2 + 12

=> - 2x = 14

=> x = $\dfrac {- 14}{2}$

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Hence, The required answer is : x = - 7

~ Hope it helps!

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