Answer:
0.5375
Step-by-step explanation:
The point estimate of proportion of all Americans who are in favor of outlawing cheese can be computed as
p=x/n
Here. x is the number of favorable outcomes and n is sample size.
We are given that x=2150 and n=4000, So,
p=2150/4000
p=0.5375.
Thus, the point estimate of proportion of all Americans who are in favor of outlawing cheese is 0.5375.
The Lagrangian is
with critical points where the partial derivatives vanish.
Substitute 
into the last equation and solve for 
:
Then we get two critical points,
We get an absolute maximum of 
at the second point, and an absolute minimum of 
at the first point.
25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
4.23 x 10 to the 4, 2 x 10 to the 3, 9.2 x 10 to the 6, 4 x 10 to the 3, 8 x 10 to the 7, and 3.2 x 10 to the 10.
Step-by-step explanation:
I will explain in the comments to this response
A6 = -8
a15= -62
There are (15 - 6) terms in between, therefore 9 terms in between.
-8 to -62 ... there is a difference of 54
54 ÷ 9 = 6
Therefore it gets -6 each term.
a6 = -8, a7= -14, a8 = -20 ......
