Given:
The expression is:

To find:
The integration of the given expression.
Solution:
We need to find the integration of
.
Let us consider,

![[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ccos%202x%3D2%5Ccos%5E2x%2C1-%5Ccos%202x%3D2%5Csin%5E2x%5D)

![\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Ctan%20%5Ctheta%20%3D%5Cdfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D%5Cright%5D)
It can be written as:
![[\because 1+\tan^2 \theta =\sec^2 \theta]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ctan%5E2%20%5Ctheta%20%3D%5Csec%5E2%20%5Ctheta%5D)


Therefore, the integration of
is
.
Answer:
x = 6.7
Step-by-step explanation:
We know that 3.5 + x = 10.2, so if we do inverse operations we can find out the value of x.
10.2 - 3.5 = 6.7
we can check our work by substituing it back in the equation for x
6.7 + 3.5 = 10.2
so now we know that x = 6.7. I hope this helps :)
Answer:
option B is correct. Once have a look to this solution that I have answered
Answer:
15<em>y</em> = -28 <em>x</em> + 205.
Step-by-step explanation:
Slope intercept form of equation is <em>y = mx + c</em> where m is slope and c is the y intercept.
Now slope of line passing through points (-5, 23) and (10, -5):

Now equation of line:
<em> y = mx + c</em>
substituting the value of m in above expression,

Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,



So equation of line in slope intercept form:
Further solving,
15<em>y</em> = -28 <em>x</em> + 205.
45.864, because 57.33 divided by 100 is 0.5733 that multiplied by 80 is 45.864