Answer:
solution:-We know that for any two finite sets A and B, n(A∪B)=n(A)+n(B)−n(A∩B).
Here, it is given that n(A)=20,n(B)=30 and n(A∪B)=40, therefore,
n(A∪B)=n(A)+n(B)−n(A∩B)
⇒40=20+30−n(A∩B)
⇒40=50−n(A∩B)
⇒n(A∩B)=50−40
⇒n(A∩B)=10
Hence, n(A∩B)=10
Step-by-step explanation:
hope it helps you friend ☺️

the -7 is found there twice, so it has a multiplicity of 2
the +7 is there thrice, so it has multiplicity of 3
Answer:
The 1st, 3rd, and 5th statements are correct.
Step-by-step explanation:
YZ has the same angle as XY, so the length is the same.
A^2+B^2=C^2 shows that XZ equals 9 sqrt 2 cm.
The hypotenuse is always the longest segment in the triangle.
87.5% of 104
87.5% x 104 = 91 homes handed out candy