The key features of the above given functions are correctly matched to their corresponding definition.
<h3>Definition of terms</h3>
- Negative sections of the graph: They are the parts where the graph is below the x-axis. That is option C.
- End behaviour: This is what happens to the graph on the far left or far right. That is option E.
- Positive sections of the graph: This is the parts where the graph is above the x-axis. That is option D.
- Intercepts: This is the points where the graph crosses an axis. That is option B
- Relative extrema: This is the points of relative minimum or maximum in a graph. That is option A.
Learn more about graphs here:
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Answer:
A. EG = √3 × FG
D. EG = √3/2 × EF
E. EF = 2 × FG
Step-by-step explanation:
∵ tan 60 = √3
∵ tan60 = EG/GF
∴ EG/GF = √3
∴ EG = √3 × GF ⇒ A
∵ m∠F = 60°
∵ sin60 = √3/2
∵ sin 60 = EG/EF
∴ √3/2 = EG/EF
∴ EG = √3/2 × EF ⇒ D
∵ cos60 = 1/2
∵ cos60 = GF/EF
∴ GF/EF = 1/2
∴ EF = 2 × GF ⇒ E
The function is L = 10m + 50
Here, we want to find out which of the functions is required to determine the number of lunches L prepared after m minutes
In the question, we already had 50 lunches prepared
We also know that he prepares 10 lunches in one minute
So after A-lunch begins, the number of lunches prepared will be 10 * m = 10m
Adding this to the 50 on ground, then we have the total L lunches
Mathematically, that would be;
L = 10m + 50
Answer:
should be 6cm
Step-by-step explanation:
if you are looking at a cube
