The question is incomplete, as the depth of the hook isn't given in the question. However, using a proposed depth for the hook, we could give a stepwise solution to the exercise.
Answer:
Kindly check explanation
Step-by-step explanation:
If given a hook depth of 6 meters, and a distance of 8 m(fishing line from hook) at the the Same depth, then the distance between rose and the fish, x can be calculated, using the relation.
Hypotenus² = opposite² + adjacent²
(refer to attached picture)
x² = 6² + 8²
x² = 36 +. 64
x² = 100
x = sqrt(100)
x = 10 meters
You can use the actual depth value to obtain the actual solution to your question.
Answer:
There is not a slope perpendicular to the lie x = -6
Step-by-step explanation:
In this equation, you are given a line, x = -6.
This is in fact a line with an undefined slope. The slope for a perpendicular intersection is the opposite reciprocal of the slope.
Eg. If you have the line y = 2x
The reciprocal is y = 1/2x, the opposite means negative
So the slope that would intersect this line perpendicularly is y = -1/2x.
There is an undefined slope in this, therefore, you cannot find the slope for a line perpendicular to x = -6.
If it were an option, I would choose "no slope"
let's recall the remainder theorem.
we know that (x-1) is a factor, that means x -1 = 0 or x = 1.
since we know that (x-1) is a factor, then dividing the polynomial by it will give us a remainder of 0, which correlates with saying that f(1) = 0, in this case, so we can simply plug in "1" as the argument, knowing it gives 0.
![f(x)=3x^3+kx-11\\\\[-0.35em]~\dotfill\\\\\stackrel{0}{f(1)}=3(1)^3+k(1)-11\implies \stackrel{f(1)}{0}=3+k-11\implies 0=-8+k\implies 8=k](https://tex.z-dn.net/?f=f%28x%29%3D3x%5E3%2Bkx-11%5C%5C%5C%5C%5B-0.35em%5D~%5Cdotfill%5C%5C%5C%5C%5Cstackrel%7B0%7D%7Bf%281%29%7D%3D3%281%29%5E3%2Bk%281%29-11%5Cimplies%20%5Cstackrel%7Bf%281%29%7D%7B0%7D%3D3%2Bk-11%5Cimplies%200%3D-8%2Bk%5Cimplies%208%3Dk)
Answer:
volume of cone=1/3 πr²h=1/3 ×π×5²×15=125πcm³
Answer:5
Step-by-step explanation:
Since Michelle (he ? ) has 11/12 quarts of paint, and need 1/6 per quart to paint, we do 11/12 / 1/6 = 11/2, or 5.5. We cannot paint .5 of a block, so Michelle can only paint 5 quarts.
