Answer:
1/6
Step-by-step explanation:
Given:
- Length of the trough: 9 ft
=> The volume of the trough: V =
* (b * h) (1)
- An isosceles right triangle with hypotenuse 2 feet
=> the other two sides of the triangle is:
= tan(45 degrees) = h/(b/2)
<=> b = 2h substitute in (1), we have:
V =
*(2h *h) = 9
Take derivative of volume with respect to time to find equation for rate of filling the trough
dV/dt = 2 * 9 *h dh/dt = 18h dh/dt
<=> dh/dt = dV/dt /(18h)
As we know that, dV/dt = 2
So, dh/dt = 2 / 18h = 1/9h
<=> V = t * rate = 2 * 2 = 4
But V = 9
<=> 9
= 4
<=> h = 2/3
The rate is the height h feet of the water in the trough changing 2 minutes after the water begins to flow:
dh/dt = 1/(9h) = 1/(9 * 2/3) = 1/6
Let one side of the triangle be x,
Now, using Pythagoras Theorem,
x²+ x²= 24²
X= 12√2
Finally, using the area of triangle formula- 1/2 x 12√2 x 12√2= 144 feet
Step-by-step explanation:
f(x) = 2x
g(x) = x² + 8
(f × g)(x) = f(x) × g(x)
= 2x(x² + 8)
= 2x.x² + 2x. 8
= 2x³ + 16x
(f×g)(x) = 2x³ + 16x