Which is the solution for log(3x - 1) + log 2 = log 4 + log (x + 2) ?
2 answers:
Answer:x=1
Step-by-step explanation:
log(3x-1)+log2=log4+log(x+2)
log(2(3x-1))=log(4(x+2))
Cancel log on both sides
2(3x-1)=4(x+2)
Open brackets
6x-2=4x+8
Collect like terms
6x-4x=8+2
10x=10
Divide both sides by 10
10x/10=10/10
x=1
Answer:
x=5
Step-by-step explanation:
log(3x-1)+log2=log4+log(x+2)
log(2(3x-1))=log(4(x+2))
Cancel log on both sides
2(3x-1)=4(x+2)
Open brackets
6x-2=4x+8
Collect like terms
6x-4x=8+2
2x=10
Divide both sides by 2
2x/2=10/2
x=5
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