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3 years ago

Find the areas of the trapezoids.

Mathematics

2 answers:

LenKa [72]3 years ago

6 0

Answer:

10.5 units²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = $\frac{1}{2}$ h (a + b)

where h is the height and a, b the parallel bases

Here h = OS = 3, a = OC = 5 and b = SK = 2, thus

A = 0.5 × 3 × (5 + 2) = 1.5 × 7 = 10.5 units²

geniusboy [140]3 years ago

4 0

Answer:

Step-by-step explanation:

a = 2 units

b = 5 units

height (h) = 3 units

$Area=\frac{(a+b)*h}{2}\\\\=\frac{(2+5)*3}{2}\\\\=\frac{7*3}{2}=\frac{21}{2}\\\\=10.5square units$

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Five angles are set at a point. The measurement of each angle is one of five consecutive whole numbers. Set up and solve the equ

grandymaker [24]

Answer:

Step-by-step explanation:

5 0

3 years ago

Which one of the following is not closed under the operation being performed

Sergeu [11.5K]

Remember that polynomials are closed under addition, subtraction, and multiplication, but they are not closed under division. The only division you have there is B; therefore the correct answer is B.

A. $(14x-2)3(x-2)=14 x^{2} -90x+10$ . The result is still a polynomial; therefore, answer A is incorrect.

B. $\frac{(14x-2)}{3(x-2)} = \frac{14}{3}$ with a remainder of 26. The result is not a polynomial anymore; therefore, B is the correct answer.

C. $(14x-2)+3(x+2)=17x+4$ . The result is still a polynomial; therefore, answer C is incorrect.

D. $(14x-2)+3(x+2)=17x+4$ . The result is still a polynomial; therefore, answer D is incorrect.

4 0

3 years ago

Find the second derivative y= x^2lnx

Dimas [21]

First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx

now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer

3 0

3 years ago

3m+n=10<br>5m-2n=2<br>what is the answer for this one

svlad2 [7]

Answer:

m = 2

n = 4

Step-by-step explanation:

Ok so to solve this, you want to get it so there is only one variable and then solve that equation. To do this, you can start by doing:

3m + n = 10

multiply both sides by 2

6m + 2n = 20

now, in both of your equations you have 2n so you can add the two equations:

6m + 2n = 20

+ 5m - 2n = 2

11m = 22

divide both sides by 11

m = 2.

Now, plug this value into the original equation, 3m + n = 10:

3 * 2 + n = 10

6 + n = 10

subtract 6 from both sides

n = 4

6 0

3 years ago

You were testing orange juice recipes it’s recipe calls for orange juice concentrate and water mix one has 4 cups of concentrate

Sav [38]

Answer:

First mixed is the most orangey.

Step-by-step explanation:

First:

$Orange\ juice\ concentrate=4\ cups\\\\Water=6\ cups\\\\Tota\ content=4+6=10\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{4}{10}\times 100=40\%$

Second:

$Orange\ juice\ concentrate=1\ cups\\\\Water=3\ cups\\\\Tota\ content=1+3=4\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{1}{4}\times 100=25\%$

Third:

$Orange\ juice\ concentrate=2\ cups\\\\Water=4\ cups\\\\Tota\ content=2+4=6\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{2}{6}\times 100=33.33\%$

First mixed has highest percentage of orange juice. Hence first mixed is the most orangey.

4 0

3 years ago