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4 years ago

Question 1 (1 point)

Mathematics

2 answers:

NikAS [45]4 years ago

8 0

Answer:

Step-by-step explanation:

4(x - 1)2 + 3y

12-4+2+6

8+2+6

10+6

16 i think

valentina_108 [34]4 years ago

5 0

Answer:

Step-by-step explanation:

4(3 - 1) 2 + 3(2)

12 - 4 + 2 + 6

8 + 8

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On a zip-line course, you are harnessed to a cable that travels through the treetops. You start at platform A and zip to each o

Shalnov [3]

Answer:

We have to travel 26.93 units from platform B to C.

Step-by-step explanation:

Length of a segment having coordinates $(x_1,y_1)$ and $(x_2,y_2)$ is determined by the formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

From the graph attached,

Coordinates of the points B and C are (-25, -20) and (-15, 5) respectively.

Distance between these points B and C Or length of BC will be,

BC = $\sqrt{(-25+15)^2+(-20-5)^2}$

= $\sqrt{100+625}$

= $\sqrt{725}$

= $5\sqrt{29}$

= 26.93 units

Therefore, we have to travel 26.93 units from platform B to C.

7 0

4 years ago

Read 2 more answers

Craig collects stamps he collected a total of 150 stamps if 88% of the stamps be collected were foreign how many stamps did he c

sertanlavr [38]

Answer:

18 Non Foreign Stamps

Step-by-step explanation:

Given data

Total stamps= 150

Foreign Stamps= 88% of the total stamps

Hence the number of foreign stamps is

=88/100*150

=0.88*150

=132 Foreign Stamps

The number of stamps that is Non Foreign Stamps is

=150-132

=18 Non Foreign Stamps

8 0

3 years ago

Find the slope of the line going through the points (5, 2) and (0, -13).

never [62]

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (5, 2) and (0, -13). Substitute:

$m=\dfrac{-13-2}{0-5}=\dfrac{-15}{-5}=3$

<h3>Answer: slope = 3</h3>

6 0

4 years ago

Read 2 more answers

find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.

DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

Or, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}$

Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × $\frac{171}{4}$

∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

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4 years ago

Student finished eighth of homework problem in the class If the ratio of problem she finish to problem she still had left was 4.

omeli [17]

5 homework problems because 4+1=5

6 0

3 years ago