Start at (0, 135) and work your way down 15 and over one each time. Your next point would be (1, 120)
4-0-0
2-1-1
1-2-1
1-0-3
0-1-3
Those are just the ones I can think of so about 5 ways
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The best and most correct answer among the choices provided by the question is </span><span>C.{–10, –4.3}</span> .
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Hope my answer would be a great help for you. </span>
Number of tickets: T.
Number of customers: c
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150
For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)
Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150
