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MaRussiya [10]
3 years ago
14

Solve the problem.

Mathematics
1 answer:
miskamm [114]3 years ago
7 0

Answer:

0.7

Step-by-step explanation:

Find Explanation attached

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The answer is, none because they are both different substances.

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 Solve the system of inequalities and indicate all the integers which are in the solution set:
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1.) a>10
2.) a<3.5
How I got it: 1.) Subtract 3 from both sides, leaving -2a<10.
2.) Divide by -2 from both sides, remember to flip the inequality sign when dealing with negatives. This leaves you with a>10.
For number 2.) I divided both sides by 5, leaving a<3.5, though this answer may be wrong.
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A certain city's population is 120,000 and decreases 1.4% per year for 15 years.
mart [117]

Answer:

  • Decay Problem.
  • Decay rate,  r = 0.014
  • Initial Amount =120,000
  • P(t)=120000(0.986)^t
  • P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

  • Since the population decreases, it is a Decay Problem.
  • Decay rate, r=1.4% =0.014
  • Initial Amount =120,000

Therefore, the function is:

P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t

When t=10 years

P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)

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Katie draws two chords in a circle in a certain way. She then draws in four segments between adjacent endpoints of the chords to
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Answer: The answer that is not true is choice D.

If Katie drew those chords and those line segments to form a square, then the diagonals would have to be congruent. The only way to have them would be through the center, therefore they must be diameters.

And if it is a square, then the diagonals are perpendicular bisectors meaning the angles would be right angles not acute or obtuse as in Choice D. <span />
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The perimeter (P) is the sum of all sides:

\begin{gathered} (2x^2-6x+25)+(5x^3+6x^2-3x+4)+(x^3-2x^2+8x+9)+(3x^4+2x^3+8x+7) \\ 2x^2-6x+25+5x^3+6x^2-3x+4+x^3-2x^2+8x+9+3x^4+2x^3+8x+7 \\ 3x^4+5x^3+x^3+2x^3+2x^2+6x^2-2x^2-6x-3x+8x+8x+25+4+9+7 \\ 3x^4+8x^3+6x^2+7x+45 \end{gathered}

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