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Snowcat [4.5K]
3 years ago
12

I don't get what it is asking me to do

Mathematics
1 answer:
Ksju [112]3 years ago
7 0
What you do here is you input 11 in as a value of x:
t=3n-7\\
t=3(11)-7\\
t= 33-7\\\\
t=26
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Montoya Construction needs to borrow $375,000 to build a road to install utilities in a small subdivision. It borrows the funds
MissTica

Step 1

Given;

\begin{gathered} \text{Principal(p)= \$375000} \\ \text{First rate = 8\%=}\frac{8}{100}=0.08 \\ \text{Second rate = 20\%= }\frac{20}{100}=0.2 \\ \text{Time}=\frac{90}{365}=\frac{18}{73} \end{gathered}

Required; To find the difference in interest between the two periods.

Step 2

State the formula for simple interest

A=P(1+rt)

Step 3

Find the interest when the rate is 8%

\begin{gathered} A=375000(1+(0.08\times\frac{18}{73}) \\ A=375000(1+\frac{36}{1825}) \\ A=\text{\$}382397.26 \end{gathered}

Therefore the interest is given as;

A-P=382397.26-375000=\text{\$}7397.26

Step 4

Find the interest in 1980 with a 20% rate

\begin{gathered} A=375000(1+(0.2\times\frac{18}{73}) \\ A=\text{\$}393493.15 \end{gathered}

The interest is given as;

A-p=393493.15-375000=\text{\$}18493.15\text{ }

Step 5

Find the difference in interest between the two rates.

\text{\$}18493.15-\text{\$}7397.26=\text{\$}11095.89

Hence, the difference in interest between the two rates = $11095.89

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