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Katena32 [7]
3 years ago
11

I really need help with this !

Mathematics
1 answer:
user100 [1]3 years ago
8 0

It is obvious that Triangle BCD is congruent to Triangle EFG. EFG is twice the size of BCD.

Put the lengths into the pythagorean theorem equation. (the longest side is the hypotenuse)

So for Triangle BCD

3^2+b^2=5^2

(3×3)+b^2=(5×5)

9+b^2=25

So what plus 9 equals 25?

16

the square root of 16 is 4 so 4^2=16

9+16=25

Now since we know that Triangle EFG is twice the size of BCD remake the equation but the numbers will be:

6^2+8^2=10^2

Now check

(6×6)+(8×8)=(10×10)

36+64=100

100=100

So for Triangle EFG X=8

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Odd numbers take the form 2n-1, where n\ge1 is an integer. When n=400, the last odd number would be 799. So we're adding

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###

We could also make use of the formulas,

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S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000

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