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likoan [24]
3 years ago
9

Please help me with this homework

Mathematics
2 answers:
jenyasd209 [6]3 years ago
8 0

Answer:

the answer is 45

Step-by-step explanation:

first you do 9 divided by 12 you get .75

then you multply that by 60  because there is 60 secs in a minute

Have a good day and please mark me brailest

satela [25.4K]3 years ago
3 0

Answer:

45

Step-by-step explanation:

9x60=540

540/12= 45

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What is the equation for 5 units left and 3 units up from f(x)=x
erastovalidia [21]

The new equation after shifting will be:

g(x) = (x+5)+3\\g(x) = x + 8

Step-by-step explanation:

Function trnafomations upward and left are defined as:

Upward:

f(x) => f(x)+b where b is an integer

Left:

f(x) => f(x+b) where b is an integers

Given function is:

f(x) = x

Shifting the function 5 units left

g(x) = f(x+5) => x+5\\g(x) = x+5

Shifting the function upward 2 units

So,

g(x) = (x+5)+3\\g(x) = x + 8

The new equation after shifting will be:

g(x) = (x+5)+3\\g(x) = x + 8

Keywords: Functions, shifting

Learn more about functions at:

  • brainly.com/question/4054269
  • brainly.com/question/4163549

#LearnwithBrainly

3 0
3 years ago
Plsplsplsplsplsplspslpslsplspslpslpslsplsplspslsp
nikdorinn [45]

Answer:

192

Step-by-step explanation:

Fist you do 4x6x4, then 6x8x2 and add em together and you get 192! :)

5 0
3 years ago
Read 2 more answers
Simplify the expression. Write the answer using scientific notation. (4 × 108)2 16 × 1016 1.6 × 1016 8 × 1017 1.6 × 1017
sammy [17]

Answer:

\large\boxed{\bigg(4\times10^8\bigg)^2=1.6\times10^{17}}

Step-by-step explanation:

\text{The sicientific notation:}\ a\times10^k,\ \text{where}\ 1\leq a10\\\\=1.6\times10\times10^{16}\qquad\text{use}\ a^n\times a^m=a^{n+m}\\\\=1.6\times10^{17}

6 0
3 years ago
Evaluate the expression when f=6 12f+3
Ratling [72]

Answer:

75

Step-by-step explanation:

Substitute 6 for f

12f+3=

12*6+3=

72 + 3 = 75

4 0
3 years ago
Read 2 more answers
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
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