Answer:
A) 0.1 a, 0.9 A
Explanation:
According to the given information, all the individuals in the founder population had free earlobes. Since the allele for the free earlobes (A) is dominant over the one for the attached earlobes (a), the genotype of each of the homozygous dominant founder individual would be "AA". Humans are diploid and one individual has two alleles for each gene in its genome. Total number of alleles for the earlobe in the founder population = 10 x 2 = 20.
Frequency of dominant allele, A in the founder population = total number of homozygous dominant individuals x 2 + the total number of heterozygous genotype / total alleles for the earlobe in the population. There were 8 homozygous dominant and 2 heterozygous dominant individuals in the population.
So, frequency of dominant allele = 8 x 2 + 2 / 20 = 16 + 2 / 20 = 18/20 = 0.9
Since p+q=1; frequency of recessive allele "a" = 1-p = 1-0.9 = 0.1
Stroke Volume
Heart Rate
Cardiac Output
Systolic
Diastolic
Volume and Pressure of Blood Cells
Eating salt<span> raises the amount of </span>sodium<span> in </span>your<span> bloodstream and wrecks the delicate balance, reducing the ability of </span>your<span> kidneys to remove the </span>water<span>. The result is a </span>higher blood pressure due to the extra fluid and extra strain on the delicate blood<span> vessels leading to the kidneys.</span>
Answer:
This process can be performed using immunofluorescence analysis via antibodies.
Explanation:
<u>To test for the hypothesis</u>
To test for the hypothesis we have to analyze whether the neuronal phenotype is due to the binding of laminin to integrins, and this will enable us to determine which integrins are abundantly expressed on the neuronal cell membrane. This process can be performed using immunofluorescence analysis via antibodies
Finally when no differentiation markers are expressed in the laminin coated plates with mutant cells we can now say that it expresses integrins
