Question

In the nth term of a sequence is n2+50 what are the first 3 terms

Answer 1

Would assume this to be:  n² + 50

First term, n=1,  n² + 50 = 1² + 50 = 1*1 + 50 = 1 + 50 = 51

Second term, n=2,  n² + 50 = 2² + 50 = 2*2 + 50 = 4 + 50 = 54

Third term, n=3,  n² + 50 = 3² + 50 = 3*3 + 50 = 9 + 50 = 59

First three terms are:   51, 54, & 59.