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3 years ago

7

Mr. Matthewson increased the amount of weight he lifted each morning from 80 pounds to 90 pounds by what percentage did mr. matt

hewson increase the amount of weight he lifted

1 answer:

tatuchka [14]3 years ago

4 0

Answer:

112.5%

Step-by-step explanation:

90/80 = 1.125

1.125 * 100 = 112.5

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What is the answer to<br> 1. b+4=2b-5<br> 2. -6-29=5x-7<br> 3. 10h+12=8h+4<br> 4. 7a-17=4a+1

RoseWind [281]

Answer:

b=9

(assuming you meant -6x) x = -2

h = -4

a = 6

Step-by-step explanation:

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2 years ago

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dolphi86 [110]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A study showed that 25% of the students drive themselves to school. Based on the suggested probability, in a class of 18 student

Gwar [14]

Answer:

B) 0.283

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

25% of the students drive themselves to school.

This means that $p = 0.25$

Class of 18 students

This means that $n = 18$

What would be the probability that at least 6 students drive themselves to school?

This is

$P(X \geq 6) = 1 - P(X < 6)$

In which

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.25)^{0}.(0.75)^{18} = 0.006$

$P(X = 1) = C_{15,1}.(0.25)^{1}.(0.75)^{17} = 0.034$

$P(X = 2) = C_{15,2}.(0.25)^{2}.(0.75)^{16} = 0.096$

$P(X = 3) = C_{15,3}.(0.25)^{3}.(0.75)^{15} = 0.17$

$P(X = 4) = C_{15,4}.(0.25)^{4}.(0.75)^{14} = 0.213$

$P(X = 5) = C_{15,5}.(0.25)^{5}.(0.75)^{13} = 0.199$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.006 + 0.034 + 0.096 + 0.17 + 0.213 + 0.199 = 0.718$

$P(X \geq 6) = 1 - P(X < 6) = 1 - 0.718 = 0.282$

Closest option is B, just a small rounding difference.

4 0

3 years ago

Julio’s father is four times as old is Julio. The sum of their ages is no less than 55. Find the any quality that can be used to

rosijanka [135]

Answer:

Step-by-step explanation

dont really understand the question but you can see if it is the correct answer

represent julios age as x

represnt julios father age as 4x

so x+4x=5x

5x<55

not sure if this is correct bare that in mind

3 0

3 years ago

Differentiate. F(x) = (x3 - 3)2/3 2x f'(x) - 3 8 O f'(x) = 3 8 2x2 f'(x) 3 VX3 -8 f(x) 3 V3-8

oee [108]

Answer:

$f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } }$

Step-by-step explanation:

$f(x) = ( {x}^{3} - 8)^{ \frac{2}{3} } \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2} - 0) \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2 - 3}{3} } \times 3 {x}^{2} \\ \\ f'(x) = 2{x}^{2}( {x}^{3} - 8)^{ \frac{ - 1}{3} } \\ \\ f'(x) = \frac{2{x}^{2}}{( {x}^{3} - 8)^{ \frac{ 1}{3} } } \\ \\ \huge \red{ \boxed{ f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } } }}$

3 0

3 years ago