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Arlecino [84]
3 years ago
13

If they immediately ran in opposite directions with speeds of 180 feet per minute and 120 feet per minute respectively, how many

minutes would pass before they were 2,420 feet apart?
Mathematics
2 answers:
Damm [24]3 years ago
8 0
This is like half the question, but I guess you got the important stuff down...lol. Anyways, the runners run for the same amount of time.  They both stop when the distance between them in 2420, so the thing that's different is their rates, which means that the one that runs faster goes farther than the one that runs slower.  But we don't know the distance they each run, so we can call the distance the faster guy runs "d" and the other distance "2420-d".  Rates are 120 and 180, respectively.  Since d = rt and the time is the same for both, we solve for t to get that t = d/r.  Set up the ratios and cross multiply to solve for d: \frac{d}{120} = \frac{2420-d}{180} and 180d=290400-120d.  300d=290400 and d = 968.  Go back to your original equation of d=rt and sub in the d of 968 to solve for t: d=120t so 968=120t and t = 8.06 minutes.
Olin [163]3 years ago
5 0
2420 / (180 + 120) = 8 2/3 minutes.
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8 0
3 years ago
8. A company makes electronic components for TV's. 95% pass final inspection (and 5% fail and need to be fixed). 120 components
Taya2010 [7]

Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.

For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

Probability of <u>exactly x successes on n repeated trials, with p probability</u>, and has variance given by:

V(X) = np(1 - p)

In this problem:

  • 95% pass final inspection, hence p = 0.95
  • 120 components are inspected in one day, hence n = 120.

The variance is given by:

V(X) = np(1 - p) = 120(0.95)(0.05) = 5.7

The variance of the number that pass inspection in one day is 5.7.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

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