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Katen [24]
3 years ago
13

What is the slope of the line passing through (1, 2) and (3, 8)?

Mathematics
2 answers:
saveliy_v [14]3 years ago
6 0

Answer:

Option C is correct.

Step-by-step explanation:

Points given are

(1,2) and (3,8)

The formula used for slope is:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

x₁ = 1, x₂=3, y₁=2 and y₂=8

m=\frac{8-2}{3-1}\\m=\frac{6}{2}\\m=3

So, slope =3

Option C is correct.

kipiarov [429]3 years ago
5 0

Answer:

The slope of the line passing through (1,2) and (3,8) is 3.

Step-by-step explanation:

Slope formula is y2-y1/x2-x1

y2=8

y1=2

x2=3

x1=1

8-2/3-1

8-2=6

3-1=2

6/2=3

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A=s^2

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4 0
4 years ago
An online photo services charge $20 to make a photo book with 16 pages each extra page cost a dollar 75 the cost to ship the com
Alisiya [41]

Answer:

The expression to determine the total cost in dollars is y=25+0.75x.

Step-by-step explanation:

Given:

Service charge to make a photo book = $20

Cost per extra page = $0.75

Cost to ship the complete photo book = $5

We need to write expression to determine the total cost in dollars.

Solution:

Let the number of extra pages be denoted by 'x'.

Also Let the Total cost be denoted by 'y'.

Now we can say that;

Total cost will be equal to sum of Service charge to make a photo book and  Cost per extra page multiplied by number of extra pages and Cost to ship the complete photo book.

framing in equation form we get;

y=20+0.75x+5\\\\y=25+0.75x

Hence the expression to determine the total cost in dollars is y=25+0.75x.

3 0
3 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

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