Ask question

Ask question

All categories

3 years ago

10

How to solve this equation y=-2+6 and 3y-x+3=0

1 answer:

nikitadnepr [17]3 years ago

8 0

Y=0 and x=3 there that's what I got

You might be interested in

In ΔQRS, r = 89 inches, s = 32 inches and ∠Q=116°. Find ∠R, to the nearest degree.

allsm [11]

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

3 0

3 years ago

Root 3 cosec140° - sec140°=4<br>prove that<br><br>

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

<u>Proof:</u>

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

$\frac{4(sin(420-140)) }{sin280}$

= $\frac{4sin280}{sin280}\\ = 4 \ Proved!$

3 0

3 years ago

103,727,495 in a word form

3241004551 [841]

103,727,495 in word form is: one hundred three million, seven hundred twenty-seven thousand, four hundred ninety-five.

3 0

3 years ago

16 > - 8 + x<br><br> A. x > 24<br><br> B. x < 24<br><br> C. x > 8<br><br> D. x < 8

xeze [42]

Answer:

B. x < 24

Step-by-step explanation:

16 > - 8 + x

+8 > +8 + x Add 8 to both sides

24 > x

Final answer: x < 24

6 0

3 years ago

A board of length 7 divided by the quantity x minus 2 end of quantity meters was cut into two pieces. If one piece is 3 divided

bulgar [2K]

Answer:

Length of other board $=\frac{4x+20}{x^{2} -4}$ metres

Step-by-step explanation:

Given: Length of board = $\frac{7}{x-2}$ metres

Length of board was divided into two.

Length of one piece = $\frac{3}{x+2}$ metres

Let $l$ = length of the other board

Length of the other board = Length of board - Length of one piece

So, $l=\frac{7}{x-2}-\frac{3}{x+2}$

$l=\frac{7(x+2)-3(x-2)}{(x-2)(x+2)} \\\\l=\frac{7x+14-3x+6}{x^{2} -4} \\\\l=\frac{4x+20}{x^{2} -4}$

Thus, length of the other board $=\frac{4x+20}{x^{2} -4}$ metres

4 0

3 years ago