How to solve this equation y=-2+6 and 3y-x+3=0

Mathematics

1 answer:

nikitadnepr [17]4 years ago

8 0

Y=0 and x=3 there that's what I got

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Find x: 3/(x-4)(x-7) + 6/(x-7)(x-13) + 15/(x-13)(x-28) - 1/x-28 = -1/20

Novay_Z [31]

The value of x in the polynomial fraction 3/((x-4)•(x-7)) + 6/((x-7)•(x-13)) + 15/((x-13)•(x-28)) - 1/(x-28) = -1/20 is x = 24

<h3>How can the polynomial with fractions be simplified to find x?</h3>

The given equation is presented as follows;

$\frac{3}{(x - 4) \cdot (x - 7) } + \frac{6}{(x - 7) \cdot (x - 13) } + +\frac{15}{(x - 13) \cdot (x - 28) } - \frac{1}{(x - 28) } = - \frac{1}{20}$

Factoring the common denominator, we have;

$\frac{3\cdot(x - 13) \cdot(x - 28) + 6 \cdot(x - 4) \cdot(x - 28) + 15 \cdot(x - 4) \cdot(x - 7) - (x - 4) \cdot (x - 7)\cdot(x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)} + = - \frac{1}{20}$

Simplifying the numerator of the right hand side using a graphing calculator, we get;

By expanding and collecting, the terms of the numerator gives;

-(x³ - 48•x + 651•x - 2548)

Given that the terms of the numerator have several factors in common, we get;

-(x³ - 48•x + 651•x - 2548) = -(x-7)•(x-28)•(x-13)

Which gives;

$\frac{-(x - 7) \cdot(x - 28)\cdot (x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)} + = - \frac{1}{20}$

Which gives;

$\frac{-1}{(x - 4)} + = - \frac{1}{20}$

x - 4 = 20

Therefore;

x = 20 + 4 = 24

Learn more about polynomials with fractions here:

brainly.com/question/12262414

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2 years ago

What's the area of the quadrilateral

shepuryov [24]

Answer: Use the formula (base1+base2)/2 multiplied by height(3 in)

Step-by-step explanation: I can't see what the bottom base is, but lets say it is 12. 5+12=17, and 17/2=8.5. 8.5*3=25.5

Answer:25.5

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3 years ago

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Calculus question....does anyone know how to solve this?

iogann1982 [59]

$h(x)=(f\circ g)(x)$
$\sqrt{x+5}=\sqrt{g(x)+2}$
$x+5=g(x)+2$
$g(x)=x+3$

Just to check this is correct:

$(f\circ g)(x)=f(g(x))=f(x+3)=\sqrt{(x+3)+2}=\sqrt{x+5}=h(x)$