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tangare [24]
4 years ago
10

How to solve this equation y=-2+6 and 3y-x+3=0

Mathematics
1 answer:
nikitadnepr [17]4 years ago
8 0
Y=0 and x=3 there that's what I got

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umka2103 [35]
E is (0,-4)  F is (6,0)  H is (0,2) and  G is(-7,0)
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2−(−4)+3+(−6)−(−2)2, minus, left parenthesis, minus, 4, right parenthesis, plus, 3, plus, left parenthesis, minus, 6, right pare
Yuki888 [10]

Answer: 7

Step-by-step explanation:

2−(−4)+3+(−6)−(−2)2

solution:

– x – = +

– x + = –

= 2−(−4)+3+(−6)−(−2)2

= 6 + 3 + ( – 6) – ( 2 ) 2

= 9 + ( –6 ) – ( –2 ) 2

= 3 – (–2)2

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Read 2 more answers
A rectangle has a perimeter of 80. if the length is four more than twice the width, what is the length of the rectangle ​
zubka84 [21]

Answer:

28

Step-by-step explanation:

l = length

w = width

p = perimeter

w = w

l + l + w + w = p (adding all the rectangle's sides together gets us our perimeter)

l = 2w + 4 (four more than twice the width)

Substitute 2w + 4 for 'l' in the original equation

(2w + 4) + (2w + 4) + w + w = 80

Solve equation normally:

6w + 8 = 80

6w = 72

w = 72/6 = 12

(w = 12)

Length = 2w + 4

Substitute 12 for 'w':

2(12) + 4 = l

24 + 4 = l

28 = l

The length is 28

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Answer:

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