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Aleks04 [339]
3 years ago
9

When rope is selling at $.10 a foot, how many feet can you buy for sixty cents?

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
6 0
6 feet.  I just counted by tens until I reached 60, which landed me on 6.
Alla [95]3 years ago
4 0
In my opinion 6 feet.
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Linear function for f(-11)=5, slope of f= -2/3
wolverine [178]

Answer:

  f(x) = -2/3(x +11) +5

Step-by-step explanation:

The point-slope form of the equation of a line will give you the desired linear function:

  y = m(x -h) +k . . . . . for slope m through point (h, k)

You are give point (x, f(x)) = (-11, 5) = (h, k), and you are given slope m = -2/3. Putting these values into the function form gives ...

  f(x) = -2/3(x +11) +5

7 0
2 years ago
Help please it math!!!!
77julia77 [94]

Answer:

I think its B i might be wrong

Step-by-step explanation:

4 0
2 years ago
Tiles (6" by 6") can be installed at the rate of 50 per worker hour. The floor of a large lobby area (80’ by 40’) is to be cover
RideAnS [48]

Answer:

Step-by-step explanation:

Tiles (6" by 6") can be installed at the rate of 50 per worker hour. Since the tile is a square, its area is

L^2 = 6^2 = 36 inches square

So in an hour, a worker installs 50 tiles whose area is 36 inches square. Total square meters installed per hour will be 50 × 36 = 1800 inches square per hour.

If three workers are assigned to this task, their work rate will be

1800 × 3 = 5400 inches square per hour.

The floor of a large lobby area (80’ by 40’) is to be covered with these tiles. We would convert from feet to inches.

1 foot = 12 inches

80 feet = 80 × 12 = 960 inches

40 feet = 40 × 12 = 480 inches

Area of the lobby = 90 × 480 = 460800 inches square.

If the 3 workers install 5400 inches square in 1 hour,

Then then they will install 460800 inches square in

460800/5400 = 85.33 hours

Converting to the nearest whole day, it becomes

85.33/24 = 3.55

Approximately 4 days

4 0
2 years ago
What are the theorems I feel like I got at least 1 wrong already ╥﹏╥
OLEGan [10]
\begin{gathered} m\angle2=m\angle6\text{ are corresponding angles} \\ \angle2\cong\angle6\text{ are the same because the both angles are corresponding} \end{gathered}\begin{gathered} m\angle2+m\angle3=180\text{ are angles on a straight line.} \\ \text{angles on straight line =180 degree} \end{gathered}\begin{gathered} m\angle3+m\angle6=180\text{ are supplementary angles} \\ \text{supplementary angles = 180 degree} \end{gathered}\begin{gathered} m\angle2+m\angle3=m\angle3+m\angle6 \\ angles\text{ on a straight line(180 degree)=supplementary angles(180 degree)} \end{gathered}

3 0
10 months ago
Find the Area of the figure
sineoko [7]
The figure is made up of two semi-circles and one triangle

--------------------------------
Find Radius
--------------------------------
Radius = Diameter ÷ 2
Radius = 5 ÷ 2 
Radius = 2.5 ft


Area of the semi-circle = 1/2 πr²
Area of the semi-circle = 1/2 x π x (2.5)²
Area of the semi-circle = 9.82 ft²

Area of the triangle= 1/2 x base x height
Area of the triangle = 1/2 x 6 x 4
Area of the triangle = 12 ft²

Total area = 9.82 + 9.82 + 12 
Total area = 31.63 ft²

--------------------------------------------
Total Area = 31.63 ft²
--------------------------------------------
4 0
3 years ago
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