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Olegator [25]
3 years ago
7

What is the percent composition of NaHCO3?

Chemistry
1 answer:
Katarina [22]3 years ago
5 0

Answer:- Na = 27.37%, H = 1.20%, C = 14.30% and O = 57.14%

Solution:- For the percentage composition of a compound, the atomic mass of each atoms times its subscript is divided by the molar mass of the compound and multiplied by 100.

The given compound is NaHCO_3.

mass of Na = 22.99 g

mass of H = 1.008 g

mass of C = 12.01 g

mass of O = 3(16) = 48 g

Molar mass of compound = 22.99 g + 1.008 g + 12.01 g + 48 g = 84.008 g

percentage of Na = (\frac{22.99}{84.008})100

= 27.37%

percentage of H = (\frac{1.008}{84.008})100

= 1.20%

percentage of C = (\frac{12.01}{84.008})100

= 14.30%

percentage of O = (\frac{48}{84.008})100

= 57.14%


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