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3 years ago

What is the percent composition of NaHCO3?

Chemistry

1 answer:

Katarina [22]3 years ago

5 0

Answer:- Na = 27.37%, H = 1.20%, C = 14.30% and O = 57.14%

Solution:- For the percentage composition of a compound, the atomic mass of each atoms times its subscript is divided by the molar mass of the compound and multiplied by 100.

The given compound is $NaHCO_3$ .

mass of Na = 22.99 g

mass of H = 1.008 g

mass of C = 12.01 g

mass of O = 3(16) = 48 g

Molar mass of compound = 22.99 g + 1.008 g + 12.01 g + 48 g = 84.008 g

percentage of Na = $(\frac{22.99}{84.008})100$

= 27.37%

percentage of H = $(\frac{1.008}{84.008})100$

= 1.20%

percentage of C = $(\frac{12.01}{84.008})100$

= 14.30%

percentage of O = $(\frac{48}{84.008})100$

= 57.14%

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Answer:

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Explanation:

Given data:

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3 years ago

A gas sample is at 25°C and 1.0 atmosphere. Which changes in temperature and pressure will cause this sample to behave more like

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If a tube contains 2.0oz of sunscreen, how many kilograms of benzyl salicylate are needed to manufacture 325 tubes of sunscreen

Vadim26 [7]

Answer:

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So sunscreen in 325 tubes will be 2 x 325= 650 Oz. Since we know the amount of sunscreen in 325 tubes the amount of Benzyl salicylate in all 325 tubes will be 650 x 0.025 = 16.25 Oz

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has a standard free‑energy change of − 3.59 kJ / mol at 25 °C. What are the concentrations of A , B , and C at equilibrium if, a

Mamont248 [21]

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Explanation:

The reaction equation is as follows.

$A + B \rightarrow C$

Initial : 0.3 0.4 0

Change: -x -x x

Equilbm: (0.3 - x) (0.4 - x) x

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$\Delta G = -RT ln K$

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$\Delta G = -RT ln K$

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3 years ago