The liquid that is been dispensed during titration as regards this question is Titrant.
- Titration can be regarded as common laboratory method that is been carried out during quantitative chemical analysis.
- This analysis helps to know the concentration of an identified analyte.
- Burette can be regarded as laboratory apparatus.
It is used in the in measurements of variable amounts of liquid ,this apparatus helps in dispensation of liquid, especially when performing titration.
- The specifications is been done base on their volume, or resolution.
- The liquid that comes out of this apparatus is regarded as Titrant, and this is gotten during titration process, which is usually carried out during volumetric analysis.
Therefore, burrete is used in volumetric analysis.
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Answer:
here are some examples of physical change!!!
Explanation:
-An ice cube melting into water in your drink.
-Freezing water to make ice cubes.
-Boiling water evaporating.
-Hot shower water turning to steam.
-Steam from the shower condensing on a mirror.
Electrons absorb energy, as they absorb energy they go from ground state to excited state and to return to ground state electrons release energy in the form of photons producing that color.
The molecular weight of a given compound would simply the
sum of the molar weights of each component.
The molar masses of the elements are:
C = 12 amu
H = 1 amu
N = 14 amu
O = 16 amu
where 1 amu = 1 g / mol
Since there are 6 C, 5 H, 1 N and 2 O, therefore the
total molecular weight is:
molecular weight = 6 (12 amu) + 5 (1 amu) + 1 (14 amu) +
2 (16 amu)
molecular weight = 123 amu
Therefore the molecular weight of nitrobenzene is 123 amu
or which is exactly equivalent to 123 g / mol.
Answer:
The percent yield of this reaction is 42.1 % (option B)
Explanation:
Step 1: Data given
Theoretical yield of beryllium chloride = 10.7 grams
actual yield of beryllium chloride = 4.5 grams
Step 2: Calculate the percent yield for this reaction
Percent yield = (actual yield / theoretical yield) * 100%
Percent yield = (4.5 grams / 10.7 grams ) * 100 %
Percent yield = 42.1 %
The percent yield of this reaction is 42.1 % (option B)
