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erik [133]
3 years ago
7

Need help ASAP!!!

Mathematics
1 answer:
Annette [7]3 years ago
6 0

Answer:

1. Identifying parts of a triangle can help you find trigonometric ratios by seeing what side and angle measurements you have and if you have enough information to solve the triangle.

2. To use inverse trigonometric functions you should have to find the unknown measure of an angle of a right triangle when two side lengths are known. So, you simply use the same math as you would in trig ratios, but in a calculator you would have to click cos^-1, tan^-1, or sin^-1.

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PLEASE HELPPP!!!
Tems11 [23]

Answer:

a) -16t^{2}+64t\geq40

b)[2-\frac{\sqrt{6}}{2} , 2+\frac{\sqrt{6}}{2}]

(see attached picture for the number line)

This interval means that from about 0.78s to about 3.22s the ball will not be visible because it will be higher than 40 feet high.

c) h_{max}=64ft

d) t=2s

Step-by-step explanation:

a)

Basically the ball will disappear when it is higher than 40 ft, so we can build the inequality like this:

-16t^{2}+64t\geq40

this is because the function represents it's height, so when the function is greater than or equal to 40, then the ball will disappear.

b) to solve the inequality, first we need to turn the ≥ symbol to an = symbol and solve for t, so we get:

-16t^{2}+64t =40

we can move the 40 to the other side of the equation so we get:

-16t^{2}+64t-40=0

we can factor the equation so it's easier to solve, so we get:

-8(2t^{2}-8t+5) =0

which simplifies to:

2t^{2}-8t+5=0

and we can use the quadratic formula to solve this equation, so we get:

t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

so we get:

t=\frac{-(-8)\pm\sqrt{(-8)^{2}-4(2)(5)}}{2(2)}

which yields:

2\pm \frac{\sqrt{6}}{2}

and next we need to test the posible intervals to see which one makes the inequality true, the possible intervals are:

(-\infty, 2-\frac{\sqrt{6}}{2}]  for a test value of 0

[2-\frac{\sqrt{6}}{2},2+\frac{\sqrt{6}}{2}] for a test value of 1

[2+\frac{\sqrt{6}}{2},\infty) for a test value of 4

so next we test each of the values in the original inequality and see if the inequality is true:

(-\infty, 2-\frac{\sqrt{6}}{2}] for a test value of 0

-16(0)^{2}+64(0)\geq40

0\geq40 false

so this is not an answer.

[2-\frac{\sqrt{6}}{2},2+\frac{\sqrt{6}}{2}] for a test value of 1

-16(1)^{2}+64(1)\geq40

48\geq40

true, so this is an answer.

[2+\frac{\sqrt{6}}{2}, \infty) for a test value of 4

-16(4)^{2}+64(4)\geq40

-16(16)+64(4)\geq40

-256+256\geq40

0\geq40

false, so this is no answer.

So the answer is the interval:

[2-\frac{\sqrt{6}}{2},2+\frac{\sqrt{6}}{2}]

This interval means that from about 0.78s to about 3.22s the ball will not be visible because it will be higher than 40 feet high.

c) In order to find how high Penelope kick the football, we must find the vertex of the parabola which is gotten when graping the given function (see attached picture)

so we can use the following formula to find the t-value for this maximum height:

t=-\frac{b}{2a}

so we substitute the corresponding values:

t=-\frac{64}{2(-16)}

which yields:

t=2s

next, we can substitute this time into the original function to find the maximum height, so we get:

h=-16(2)^{2}+64(2)

which yields:

h=64 ft

d) We found the answer for d on the previous part where we got that t=2s

6 0
3 years ago
ZA and ZB are supplementary angles. If mZA = (5x + 25)° and m
liberstina [14]

Answer:

MZA = 140

Step-by-step explanation:

5x+25°+ x + 17°=180°(Supplimentary Angles)

6x + 42° =180°

6x =180 - 42

6x=138

(divide by 6 both sides)

X= 23

substitution X into the given angle

5x +25

5(23)+25

115+25

140

3 0
3 years ago
I haven’t done this since 7th grade sorry I just don’t remember
Softa [21]
Elimination is x=3 since you can cancel our out the 3y just add the 8 and 2 which is 10 and 18 and 12 which is 30, devide and there ya go
5 0
3 years ago
Read 2 more answers
Andrew wants to know how many 3/16 pound servings in a bag containing 7/8 pound of granola
Aleksandr-060686 [28]
Do 7/8 divided by 3/16.
Multiply by the reciprocal of 3/16 which is 16/3
7/8 x 16/3= 112/24
Simplify by dividing by 8 on top and bottom
14/3
Change it into a mixed number
Answer is 4 2/3
3 0
3 years ago
Use the functions h(x) = 2x - 5 and t(x) = 6x + 4 to complete the function operations listed below.
Rom4ik [11]

Answer:

See below for answers (in bold) and explanations

Step-by-step explanation:

Part A: (h+t)(x) = h(x) + t(x) = (2x-5) + (6x+4) = 2x - 5 + 6x + 4 = 8x - 1

Part B: (h*t)(x) = h(x) * t(x) = (2x-5) * (6x+4) = (2x)(6x) + (2x)(4) + (-5)(6x) + (-5)(4) = 12x² + 8x - 30x - 20 = 12x² - 22x - 20

Part C: h(t(x)) = h(6x + 4) = 2(6x + 4) - 5 = 12x + 8 - 5 = 12x + 3

3 0
3 years ago
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