<span>Uphill distance = 1 4/5 = 9/5 = 18/10 km
Downhill Distance = 2 7/10 = 27/10 km
Total Uphill and Downhill = 18/10 + 27/10 = 45/10 = 4.5 km
Hence total level ground = Total race km - (Uphill + Downhill)
=10 - 4.5 = 5.5 km
Hence the answer is 5.5 km.</span>
Answer:
1) M(x) = 5 + 3x
2) Dependent variable; 3 dollar bills
Independent variable: chores
3) Range is continuous
Domain is discrete
4) Range: 0 ≤ x ≤ 10
Domain: 5 ≤ M ≤ 35
Step-by-step explanation:
We are told he started with 5 number of $1 dollar bills and that every Saturday, he earns 3 more $1 dollar bill.
Thus, total number of $1 bills earned after x number of Saturdays(weekly) is;
M(x) = 5 + 3x
After 10 weeks, total number is;
M(10) = 5 + 3(10)
M(10) = 35
The dependent variable is the 3 more dollar bills earned each Saturday because it depends on chores he completed. While the independent variable is the chores because it doesn't depend on anything.
After 10 weeks, the range and domain will be;
Range: 0 ≤ x ≤ 10
For the; Domain:
For x = 1, M(0) = 5 + 3(0) = 5
M(10) = 35
Thus;
Domain: 5 ≤ M ≤ 35
The range could be all numbers in the interval from 0 to 10. Thus, it is continuous.
Whereas, the domain doesn't contain all the numbers in the interval from 5 to 35. Thus it is Discrete.
Answer:
She sell <u>2.075 kilograms</u> of pears at the farmer's market.
Step-by-step explanation:
<u><em>There is a mistake in the question some data is missing, so the correct question is below: </em></u>
<em>A farmer sells 8.3 kg of apples and pears at the farmer's market. 3 /4 of this weight is apples, and the rest is pears. How many kilograms of pears did she sell at the farmer's market?</em>
Now, to find the kilograms of pears.
Total weight of apples and pears = 8.3 kg.
Weight of apples =
of 8.3 kg.
So, to get the weight of apples:



Thus, the weight of apples = 6.225 kg.
Now, to get the weight of pears we subtract the weight of apples from the total weight of apples and pears:

Therefore, she sell 2.075 kilograms of pears at the farmer's market.