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2 years ago

What is the distance between the points (-6, 2) and (-4, 7)? Round to the nearest tenth if necessary.

Mathematics

1 answer:

klemol [59]2 years ago

7 0

Answer: distance is 5.4

Step-by-step explanation: distance between points (X1,y1) and (x2,y2) is

√(x2-X1)² + (y2-y1)² = √[(-4-(-6))² + (7-2)²] = √(2²+ 5²) =√29

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Solve the rational equation: x/x+1 = 2/x+1

Tju [1.3M]

Answer:

x = 2

Step-by-step explanation:

$\frac{x}{x+1} =\frac{2}{x+1}$

x ≠ 0

x ≠ - 2

x ≠ - 1

$\frac{x}{x+1}(x+1) =\frac{2}{x+1}(x+1)$

x = 2

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2 years ago

HELP PLEASE

kakasveta [241]

Number 1 is 6 number two is -8 and number three is -10

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3 years ago

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Which quadratic equation equation is equivalent to (x^2-1)^2 -11(^2-1) +24=0

cluponka [151]

$(x^2-1)^2-11(x^2-1)+24=0$

Use substitution: $x^2-1=t$

$t^2-11t+24=0\\\\t^2-8t-3t+24=0\\\\t(t-8)-3(t-8)=0\\\\(t-8)(t-3)=0\iff t-8=0\ \vee\ t-3=0\\\\t=8\ \vee\ t=3$

we're going back to substitution:

$x^2-1=8\ \vee\ x^2-1=3\ \ \ \ |add\ 1\ to\ both\ sides\ of\ the\ equations\\\\x^2=9\ \vee\ x^2=4$

therefore

$x=\pm\sqrt9\ \vee\ x=\pm\sqrt4\\\\\boxed{x=-3\ \vee\ x=3\ \vee\ x=-2\ \vee\ x=2}$

6 0

3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the linear equations with their x-

jolli1 [7]

Answer:

Part 1) $x-2y=2$ ----> (2,0) and (0,-1)

Part 2) $-3x+3y=7$ ----> (-7/3,0) and (0,7/3)

Part 3) $7x-y=21$ ----> (3,0) and (0,-21)

Part 4) $3x-5y=-20$ ----> (-20/3,0) and (0,4)

Step-by-step explanation:

we know that

The y-intercept is the value of y when the value of x is equal to zero

The x-intercept is the value of x when the value of y is equal to zero

Part 1) we have

$x-2y=2$

1) Find the x-intercept

For y=0

$x-2(0)=2\\x=2$

the x-intercept is (2,0)

2) Find the y-intercept

For x=0

$0-2y=2\\y=-1$

the y-intercept is (0,-1)

Part 2) we have

$-3x+3y=7$

1) Find the x-intercept

For y=0

$-3x+3(0)=7\\x=-\frac{7}{3}$

the x-intercept is (-7/3,0)

2) Find the y-intercept

For x=0

$-3(0)+3y=7\\y=\frac{7}{3}$

the y-intercept is (0,7/3)

Part 3) we have

$7x-y=21$

1) Find the x-intercept

For y=0

$7x-(0)=21\\x=3$

the x-intercept is (3,0)

2) Find the y-intercept

For x=0

$7(0)-y=21\\y=-21$

the y-intercept is (0,-21)

Part 4) we have

$3x-5y=-20$

1) Find the x-intercept

For y=0

$3x-5(0)=-20\\x=-\frac{20}{3}$

the x-intercept is (-20/3,0)

2) Find the y-intercept

For x=0

$3(0)-5y=-20\\y=4$

the y-intercept is (0,4)

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3 years ago

Find the square of i) a+ X ii). b-y

deff fn [24]

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2 years ago