Here we have to calculate the amount of 
ion present in the sample.
In the sample solution 0.122g of ion is present.
The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-
K₂SO₄ = 2K⁺ +
(Na)₂SO₄=2Na⁺ +
Thus, BaCl₂+ = BaSO₄↓ + 2Cl⁻ .
(Na)₂SO₄ and K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of ion is precipitated in this reaction.
The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.
Now the molecular weight of BaSO₄ is 233.3 g/mol.
We know the molecular weight of sulfate ion () is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of ion is present.
Or. we may write in 233.3 g of BaSO₄ 96.06 g of ion is present. So in 1 g of BaSO₄ 
g of ion is present.
Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of ion is present.
B
We can perceive this question as a vector (which has both magnitude and direction). The magnitude is the displacement and the direction is where they are headed.
Explanation:
The displacement (magnitude of the vector) for Callie, which is also equal to the distance, is; 4m + 3m = 7m while that of Sue is 5m. Therefore the displacement for Callie is greater than Sue’s.
Nonetheless the direction in the vector is the same, which is towards point C.
Learn More:
For more on vectors;
brainly.com/question/12006588
brainly.com/question/11823989
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No cations are both positive. An ionic bond has to have a positive and negative to form. Or a metal and a nonmetal if that helps.
According to oxfords dictionary, another definition for this is the ability of a computer to respond to a users input.
