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3 years ago

What volume of a 4.5 m solution of phosphate is necessary to create a 80.0 ml stock of 2.0 m phosphate solution?

Chemistry

1 answer:

11Alexandr11 [23.1K]3 years ago

3 0

Answer: V1 = 45.6 ml

Explanation:

This is a dilution process whereby the concentration of phosphate in the solution is being reduced from 4.5m to 2m. Meanwhile. In a concentration process, the concentration of the phosphate solution will be increased. It can be achieved by removing solvents.

The dilution equation will be used. The equation is as follows:

M1V1 = M2V2 where

V1 = Initial volume of phosphate solution.

M1 = Initial concentration of phosphate solution.

V2 =Final volume of phosphate solution.

M2 = Final concentration of phosphate solution .

From the information given,

M1 = 4.5

V1 = ?

M2 = 2.0

V2 = 80

4.5 × V1 = 2×80

4.5V1 = 160

V1 = 160/4.5

= 35.6 ml

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2 years ago

According to the law of conservation of mass, what should the product side of this single replacement reaction look like? A. H2

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Explanation:

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3 years ago

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2 years ago

Sighting along the C2-C3 bond of 2-methylbutane, the least stable conformation (Newman projection) has a total energy strain of

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Answer:

21 KJ/mol

Explanation:

For this question, we have to start with the linear structure of 2-methylbutane. With the linear structure, we can start to propose all the Newman projections keep it in mind that the point of view is between carbons 2 and 3 (see figure 1).

Additionally, we have several energy values for each interaction present in the Newman structures:

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-) Methyl-H eclipse: 6.0 KJ/mol

-) Methyl-methyl eclipse: 11.0 KJ/mol

-) H-H eclipse: 4.0 KJ/mol

Now, we can calculate the energy for each molecule.

Molecule A

In this molecule, we have 2 Methyl-methyl gauche interactions only, so:

(3.8x2) = 7.6 KJ/mol

Molecule B

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

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Molecule C

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

3.8 KJ/mol

Molecule D

In this molecule, we have three Methyl-H eclipse interaction, so:

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Molecule E

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

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Molecule F

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

(11)+(6)+(4) = 21 KJ/mol

The structures with higher energies would be less stable. In this case, structures B and F with an energy value of 21 KJ/mol (see figure 2).

I hope it helps!

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3 years ago