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Alex777 [14]
3 years ago
12

Phosphorus has the molecular formula p4, and sulfur has the molecular formula s8. how many grams of phosphorus contain the same

number of molecules as 7.88 g of sulfur?
Chemistry
1 answer:
Alinara [238K]3 years ago
6 0
1) Find the number of molecules in 7.88 g of sulfur

molar mass of S8 = 8*atomic mass of S = 8 * 32.0 g / mol = 256.0 g/mol

Number of moles  = mass in grams / atomic mass = 7.88 g / 256.0 g / mol = 0.0308 moles

2) Find the mass of 0.0308 moles of P4

mass = number of moles * molar mass

molar mass of P4 = 4 * atomic mass of P = 4 * 31 g/mol = 124 g/mol

mass of P4 = 0.0308 moles * 124 g/mol = 3.8192g ≈ 3.82 g.

Answer: 3.82 grams of P4 will have the same number of molecules as 7.88 g of S8 (that is 0.0308 moles of molecules)
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20 Km/hr

Explanation:

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What are tiny air sacs of the lungs where oxygen and carbon dioxide are
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the correct answer is the bronchi

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4 years ago
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If the [–OH] concentration in a bottle of Windex is 9.8 x 10^(–6) M, what is its pH and pOH and is it acidic, basic or neutral?
Hatshy [7]

Answer:

pOH = 5

pH = 9 → Solution is basic

Explanation:

We need to know that:

pH + pOH = 14

    < 7        ⇔     pH = 7    ⇔    > 7

   Acidic           Neutral           Basic

pOH = - log [OH⁻] → - log 9.8×10⁻⁶ = 5.00

pOH = 5

pH = 14 - 5 = 9

4 0
3 years ago
Equation Given : Al^(3+) + Na3PO4 ==&gt; 3Na^+ + AlPO4
Helga [31]

1 mols of Aluminium ion forms 1 mol aluminium phosphate

Molar mass of AlPO_4

  • 27+31+16(4)
  • 58+48
  • 106u

Moles of AlPO_4

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  • 0.000061/106
  • 5.75×10^{-7}
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Moles of Al3+=57.5µmol

3 0
3 years ago
Analysis of a sample of a compound composed of carbon, hydrogen, and oxygen shows that the sample contains 18.80 g of C, 2.367 g
Svet_ta [14]

Answer:

Analysis of a sample of a compound composed of carbon, hydrogen, and oxygen shows that the sample contains 18.80 g of C, 2.367 g of H, and 25.04 g of O.

The properties of the compound suggest that the molar mass should be 59.04 g/mol.

How many carbon atoms are there in one molecule of the compound?

Explanation:

Empirical formula mass is

(12g/mol*2)+(1.0g/mol*3)+(16.0g/mol*2)\\=59.0g/mol\\

Empirical formula mass =molecular formula mass

Hence,

empirical formula is same as molecular formula.

That is --- C_2H_3O_2.

So, the molecule has two carbon atoms in one molecule of the compound.

3 0
3 years ago
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