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BaLLatris [955]
2 years ago
15

Find the block labeled ? in Figure 2. What is its atomic number? How many valence electrons does it have? Which of the elements

shown in Figure 2 will it most resemble?

Chemistry
2 answers:
ra1l [238]2 years ago
7 0
That is Magnesium. its atomic number is 12 and has 2 valence electrons. it will most resemble beryllium (Be)
Vadim26 [7]2 years ago
4 0

The atomic number of the element is 12. The name of the element is magnesium. It has two valence electrons. The element it most resemble is Be, beryllium.

looking at the periodic table given in the question, we can see that the element we are looking for belong to group 2, thus, its properties will be similar to that of Be, which belong to the same group. The electronic configuration of magnesium is 2, 8, 2, this implies that, it has two electrons on its outermost shell.

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Four balloons, each with a mass of 10.0 g, are inflated to a volume of 20.0 L, each with a different gas: helium, neon, carbon m
weeeeeb [17]
On temperature 25°C (298,15K) and pressure of 1 atm each gas has same amount of substance:
n(gas) = p·V ÷ R·T = 1 atm · 20L ÷ <span>0,082 L</span>·<span>atm/K</span>·<span>mol </span>· 298,15 K
n(gas) = 0,82 mol.
1) m(He) = 0,82 mol · 4 g/mol = 3,28 g.
d(He) = 10 g + 3,28 g ÷ 20 L = 0,664 g/L.
2) m(Ne) = 0,82 mol · 20,17 g/mol = 16,53 g.
d(Ne) = 26,53 g ÷ 20 L = 1,27 g/L.
3) m(CO) = 0,82 mol ·28 g/mol = 22,96 g.
d(CO) = 32,96 g ÷ 20L = 1,648 g/L.
4) m(NO) = 0,82 mol ·30 g/mol = 24,6 g.
d(NO) = 34,6 g ÷ 20 L = 1,73 g/L.
6 0
3 years ago
Read 2 more answers
Which of the following is a product formed when K reacts with Cl2?
Stels [109]
The answer is A. 
Which is... KCI
3 0
3 years ago
Read 2 more answers
How many moles are contained in 2.3 liters of a 1.2M solution?
elena-s [515]

Answer:

\boxed {\boxed {\sf 2.76 \ mol}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We know the molarity is 1.2 M (mol\liter) and there are 2.3 liters of solution. Substitute the known values into the formula.

1.2 \ mol/liter= \frac {x}{2.3 \ liters}

Since we are solving for x, we must isolate the variable. It is being divided by 2.3 and the inverse of division is multiplication. Multiply both sides by 2.3 liters.

2.3 \ liters *1.2 \ mol/liter= \frac {x}{2.3 \ liters}* 2.3 \ liters\\2.3 *1.2 \ mol= x\\2.76 \ mol =x

In a solution with a molarity of 1.2 and 2.3 liters of solution, there are 2.76 moles.

3 0
3 years ago
Calculate the pressure of 2.50 Liters of a gas at 25.0oC if it has a volume of 4.50 Liters at
MariettaO [177]

Answer:

P_2 =0.51  atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

Volume (V2) = 4.50 L

at standard temperature and pressure;

Pressure (P1) = 1 atm

Temperature (T2) = 273 K

Pressure P2 = ??

Using combined gas law:

\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}

0.008389261745 \times 273 = 4.5P_2

P_2 =\dfrac{0.008389261745 \times 273 }{4.5}

P_2 =0.51 \ atm

4 0
2 years ago
Assuming 1 mol of Fe3+ and 2 mol of SCN- were allowed to react and reach equilibrium. 0.5 mol of product was formed. The total v
zaharov [31]

Answer:

a. 0.5 mol

b. 1.5 mol

c. 0.67

Explanation:

Fe3+ + SCN- -----> [FeSCN]2+

a. The ratio of the product to Fe3+ is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of Fe3+ was used. Leaving 0.5 mol remaining at equilibrium

b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium

c. KC =  0.5/(0.5*1.5) =  0.67

3 0
2 years ago
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