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Effectus [21]
3 years ago
9

Raj was asked to fully simplify this polynomial and put it into standard form.

Mathematics
2 answers:
Roman55 [17]3 years ago
6 0

Answer:

6x^3

Step-by-step explanation:

Sophie [7]3 years ago
4 0

Answer:6x3

Step-by-step explanation:

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Simplify there is a picture
kicyunya [14]
2 to the power of 20/3 to the power of 8. 2^20/3^8 for short.
5 0
3 years ago
Which of the following tables matches the graph below?
navik [9.2K]

Right answer is C

We can solve it with the formula

y=mx+b

b is the point where graphic starts

Table C shows us 0 by x, and -4 by y

So the graph starts at (0, -4 )

3 0
2 years ago
The times for five sprinters in a 50 meter dash were 6.72 seconds 6.4 seconds 6.08 and 7.03 seconds in 6.75 seconds right these
andreev551 [17]

Answer:

Fastest to slowest = 6.08 > 6.4 > 6.72 > 6.75 > 7.03

Step-by-step explanation:

The person who completes the 50-meter race within the shortest possible time is the fastest sprinter. Here, the third sprinter crossed the line in 6.08 seconds, whereas the 4th sprinter crossed the line in 7.03 seconds. That is why the third sprinter has won the race, and he becomes the fastest. On the contrary, the fourth person takes the most time to complete the race, meaning he is the slowest.

6 0
3 years ago
Rearrange the equation so a is the independent variable.<br><br> 3a-7= -4b+1<br><br> Please help! :)
Aleksandr-060686 [28]

Answer:

Hiii the answer would be a= -4b+8/3

7 0
3 years ago
Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
3 years ago
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