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slava [35]
4 years ago
9

A manufacturing company produces 250 units per day currently. The company's goal is to increase the number of units manufactured

per day by 50 each year. If the company meets its goal, how many units will it be producing per day 4 years from now?
Mathematics
1 answer:
ki77a [65]4 years ago
7 0

Answer:

<u>The manufacturing company will produce 450 units per day in 4 years from now.</u>

Step-by-step explanation:

Current production of the manufacturing company = 250 units per day

Additional units per day produced for every year of time = 50

Therefore, the daily production after four years will be:

Current production + Additional units per day * Number of years

Replacing with the values we have:

250 + 4 * 50 = 250 + 200 = 450

<u>The manufacturing company will produce 450 units per day in 4 years from now.</u>

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Answer:

(7,5)

Step-by-step explanation:

{2x + 4y = 34

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2x + 27 - x = 34

x=7

4y = 27 - 7

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Equivalents to 1:1 -

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A boiler has five identical relief valves. The probability that any particular valve will open on demand is 0.95. Assuming indep
Gre4nikov [31]

Answer:

a) There is a 99.99997% probability that at least one valve opens.

b) There is a 22.62% probability that at least one valve fails to open.

Step-by-step explanation:

For each valve, there are only two possible outcomes. Either it open, or it does not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.95, n = 5

(a) What is the probability that at least one valve opens?

Either no valves open, or at least one opens. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1)

So

P(X \geq 1) = 1 - P(X = 0)

P(X = 0) = C_{5,0}.(0.95)^{0}.(0.05)^{5} = 0.0000003

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000003 = 0.9999997

There is a 99.99997% probability that at least one valve opens.

(b) What is the probability that at least one valve fails to open?

Either all valves open, or at least one does not open. The sum of the probabilities of these events is decimal 1. So

P(X = 5) + P(X \leq 4) = 1

We want P(X \leq 4)

So

P(X \leq 4) = 1 - P(X = 5)

P(X = 5) = C_{5,5}.(0.95)^{5}.(0.05)^{0} = 0.7738

P(X \leq 4) = 1 - P(X = 5) = 1 - 0.7738 = 0.2262

There is a 22.62% probability that at least one valve fails to open.

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d1i1m1o1n [39]

The triangle BAC has two known measurements 30 and 90 so add those together and subtract by 180

30 + 90 = 120

180 - 120 = 60°

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