Round 1,208.7438 to the nearest hundredth.

What is the Height of tree

Nataly_w [17]

The answer is most likely 15ft.

5 0

2 years ago

PLATO

vitfil [10]

Answer:

d.)33.33%

Step-by-step explanation:

There are a total of 102 students that enjoy watching soccer most.

Of those 102, 34 are middle school students; that makes the relative frequency 34/102 = 33.33%.

7 0

2 years ago

Read 2 more answers

Two trains started moving at the same time, train A from Boston to New York, and train B from New York to Boston. The distance b

Ede4ka [16]

Answer:

After 1.7 hours

Explanation:

1. Calculate the average speed of train B

60mph = 3/4 (s) ⇒ s = 60 (4/3) mph = 80 mph

2. Build a table

When the two trains meet:

Train Average speed Distance time (distance/average speed)

mph

A 60 x x/60

B 80 240 - x (240 - x) / 80

3. Write the equation

The time, when the two trains meet, is the same for both trains:

$\dfrac{x}{60}=\dfrac{240-x}{80}\\ \\ \\ 80x=14,400-60x\\ \\ 80x+60x=14,400\\ \\ 140x=14,400\\ \\ x=14,400/140\\ \\ x=102.85miles$

4. Calculate the time:

x/60 = 102.86 / 60 = 1.7 hours

The two trains will meet after 1.7 hours

7 0

2 years ago

Please help me I will give brainlist please explain

Airida [17]

So you have to graph that on to the chart i think

3 0

2 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

2 years ago