All categories

2 years ago

Round 1,208.7438 to the nearest hundredth.

Mathematics

1 answer:

OLga [1]2 years ago

4 0

Answer:

the answer is 1,208.74

You might be interested in

The perimeter of the scalene triangle is 54.6 cm. Which equation can be used to find the value of b if side a measures 8.7 cm?

77julia77 [94]

A scalene triangle is a triangle that has 3 sides that are all different lengths.

Let these letters represent the problem:

a = 8.7

b = side 2

c = side 3

P = 54.6

To find the perimeter, we just need to add all the sides [ P = a + b + c ]

So, put what we have in the formula above.

54.6 = 8.7 + b + c

Best of Luck!

7 0

2 years ago

Read 2 more answers

2x^2-20x+100 quadratic formula

ArbitrLikvidat [17]

Answer:10

Step-by-step explanation:

7 0

2 years ago

Alonso is buying a new phone for $ 870

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

1. Get 15% of 870:

First, get 10 percent of 870, which is 87, then half that, which is 43.5

Get the 87 and add the 43.5 on it, to get the full 15%, you end up with $130.5, which is the monthly payment.

(Only problem is that im pretty sure you put an extra 0, because if you just wrote 87 dollar's then you would've got 13.05, the actual answer, but if you add an extra 0 then you end up with 130$, just to let you know.)

7 0

2 years ago

What is the value of the expression 6+18 % 3x4

natka813 [3]

You tell me buddy :)

3 0

3 years ago

A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr

Goryan [66]

Answer:

Generally the barrier width is $a = 1.9322 *10^{-9} \ m$

Step-by-step explanation:

From the question we are told that

The tunneling probability required is $T = 1 * 10^{-5}$

The barrier height is $V_o = 0.4 eV$

The electron energy is $E = 0.08eV$

Generally the wave number is mathematically represented as

$k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }$

Here m is the mass of the electron with the value $m = 9.11 *10^{-31} \ kg$

h is is know as h-bar and the value is $\= h = 1.054*10^{-34} \ J \cdot s$

$k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }$

=> $k = 3.073582 *10^{9} \ m^{-1}$

Generally the tunneling probability is mathematically represented as

$T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}$

$1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}$

=> $6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}$

Taking natural log of both sides

$ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}$

=> $-11.8776 = -2 * 3.0736 *10^{9} * a}$

=> $a = 1.9322 *10^{-9} \ m$

4 0

2 years ago