Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
B . A & b are parallel to each other
Answer:
Is there a question?
Step-by-step explanation:
can be simplified to by adding the 7 and 10 to get
.
cannot be simplified any more by combining like terms.
By distributing the 2b into the parentheses, you can simplify the expression:
Here you can just add:
Thus, the only expression that cannot simplify any more using adding like terms is the second,
.
