All categories

3 years ago

What is 45 divided by 8.0

Mathematics

2 answers:

Alexxx [7]3 years ago

7 0

Answer:

answer is 5.625

hope it helps

zhenek [66]3 years ago

5 0

5.625

40/5=5

5/8=0.625

You might be interested in

Given that there were 4 Heads in the first 7 tosses, find the probability that the 2nd Heads occurred at the 4th toss. Give a nu

tamaranim1 [39]

Answer:

The probability that the 2nd Heads occurred at the 4th toss is 5.99%.

Step-by-step explanation:

Given that there were 4 Heads in the first 7 tosses, to find the probability that the 2nd Heads occurred at the 4th toss the following calculation must be performed:

7 - 4 = 3

4/7 x 3/7 x 3/7 x 4/7 = X

0.571 x 0.428 x 0.428 x 0.571 = X

0.0599 = X

Therefore, the probability that the 2nd Heads occurred at the 4th toss is 5.99%.

6 0

3 years ago

Which expression is equivalent to7sqrt x^2/ 5 sqrt y^3<br> ?Assume y/=0,

SOVA2 [1]

Answer:

7sq rt = 2.6457513110645907 = sqrt y^3

Step-by-step explanation:

8 0

3 years ago

Which expression is equivalent to 30 + 8?

brilliants [131]

Answer:

Step-by-step explanation:

7 0

2 years ago

Linzy is having a bake sale. She has 48 chocolate chip cookies and 64 vanilla wafer

Yuliya22 [10]

Answer:

1 bag of 64

2 bags of 32

4 bags of 16

Or 8 bags of 8

Step-by-step explanation:

that's the answer I think for however your answer is there were no answers to pick from....

4 0

3 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$