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Veseljchak [2.6K]
3 years ago
6

What is 45 divided by 8.0

Mathematics
2 answers:
Alexxx [7]3 years ago
7 0

Answer:

answer is 5.625

hope it helps

zhenek [66]3 years ago
5 0

5.625

40/5=5

5/8=0.625

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What is 8/9 of 3/8?<br> A. 11/72<br> B. 2/7<br> C. 1/3<br> D. 3/7
Sedaia [141]
If you are talking about Multiplying them together then it’s 1/3 because you go 8x3
And 9x8 which makes 24/72 simply and then you get 1/3
3 0
2 years ago
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Use the diagram of the right triangle above and round your answer to the nearest hundredth.
Yakvenalex [24]

Answer:

value of a = 6.93 m

hence , (b.)

Step-by-step explanation:

the given triangle is a right angled triangle, so

by using trigonometry.

=》

\tan(a)   = \tan(30)  =  \frac{1}{ \sqrt{3} }

and we know,

=》

\tan(a)  =  \frac{a}{b}

so, by above values of tan ( a ) we get,

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\frac{a}{b}  =  \frac{1}{ \sqrt{3} }

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\frac{a}{12}  =  \frac{1}{ \sqrt{3} }

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a = 4 \sqrt{3}

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a = 6.93

hence, a = 6.93 m

4 0
3 years ago
PLEASE HURRYmy question is in the picture ​
Andreyy89
The answer t our question is the first one
I just substituted he number one in every x
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5 0
3 years ago
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3 questions in 1
MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

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3 0
2 years ago
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Masteriza [31]
I think the answer to your question might be 6
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