What is the final transformation in the composition of transformations that maps pre-image ABCD to image A"B'C"D"?
2 answers:
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Answer: x = 2
The step by step is attached to this answer, hope it helped!
Answer:
Step-by-step explanation:
1) y = 2x ----------(I)
x + y = 6 -----------(II)
Plug in y =2x in equation (II)
x + 2x = 6 {Add like terms}
3x = 6
x = 6/3
x = 2
Plugin x = 2 in (I)
y = 2*2
y = 4
<u>Check: </u>
LHS = x +y
= 2 + 4
= 6 = RHS
2)5x + 10y = 3 ------------(I)
x = (-1/2) y ------------(II)
Substitute x = (-1/2)y in (I)
Substitute y = (2/5) in equation (II)
<u>Check:</u>
Substitute x and y value in equation (I)
3) y - x = 3x + 2
y = 3x + 2 + x
y = 4x + 2 ---------------(I)
2x + 2y = 14 - y
2x + 2y +y = 14
2x + 3y = 14 ------------------(II)
Substitute y = 4x + 2 in equation (II)
2x + 3(4x +2) = 14
2x + 3*4x + 3*2 = 14
2x + 12x + 6 = 14
14x + 6 = 14
14x = 14 - 6
14x = 8
x = 8/14
x = 4/7
Substitute 'x' value in (I)
<u>Check:</u>
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Answer:
a) 40 sides
b) 6840
c) 9 gegrees
Step-by-step explanation:
interior angle= (<u>n</u><u>-</u><u>2</u><u>)</u><u>1</u><u>8</u><u>0</u>
n
so total number of sides is 40
b) Sum of interior angles= (n-2)×180
(40-2)×180
38×180
6840
c) Exterior angle = 360 ÷ n
360÷40 =9 degree