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Law Incorporation [45]
3 years ago
13

Two clothing stores are having a sale on all their dress shirts. Store A is charging $15 for each dress shirt. Store B is $18 fo

r each shirt but giving customers a coupon for a $9 discount when they check out.
Which of the following statements is true?
A. Helen bought 4 dress shirts at Store A for $75.
B. Henry bought 4 dress shirts at Store B for $72.
C. Hank bought 3 shirts from Store A and paid the same as Holly paid for 3 shirts at Store B.
D. Buying dress shirts from Store A will always be cheaper than buying dress shirts from Store B.
Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

C

Step-by-step explanation:

When the steps are followed. They both pay the same amount

Zepler [3.9K]3 years ago
7 0

Answer:

C

Step-by-step explanation:

A: Helen paid $60 at store A for 4 Dress Shirts

B:Henry bought 4 dress shirts at Store B for $63

D: (1 shirt)Store A with discount is $15 and at Store B (with $9 coupon) $9 , though it is true with one shirt, it is not certain this will happen with a greater amount of shirts.

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Three pencils cost 75p altogether. how much will it cost to buy 6 pencils?
Svetllana [295]
The cost for six pencils would be a total of 150p
The reason why is if three pencils cost 75p and you want to know what the cost of six, since three is half of six you would do this (if 3=75p then 3*2=75p*2 which is 6=150p). As shown, you multiply each side by 2 or double each side
8 0
3 years ago
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Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
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5 0
3 years ago
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A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s
Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

<em>Let </em>\hat p<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>

<u></u>

<u>Now,  point estimate (</u>\hat p<u>) is calculated as;</u>

                               \hat p=\frac{X}{n}

where, X = number of students who answered yes = 1,344

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So, Point estimate (\hat p)  =  \frac{1,344}{2,800}

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Whats the question here?
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Sauron [17]
30°

A strait line is 180°
75°+75°=150°
180°-150°=30°
5 0
2 years ago
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