[tex] 3(x + 5) - 2(x + 2) = 20 \\
3x + 15 - 2x - 4 = 20\\
5x + 11 = 20\\
5x = 9\\
x = 1\frac{4}{5} [tex]
5 - 6 = -1
2 + 7 = 9
-1 × 9 = -9
-9 would be the simplified answer.
Hope this helps!
Answer:
<u>The number is 67</u>
Step-by-step explanation:
<u>Equations</u>
Let's consider the number 83. The tens digit is 8 and the unit digit is 3. Note the tens digit's addition to the number is 80, and the unit's addition is 3. This means the tens digit adds 10 times its value, that is, 83 = 8*10 + 3.
Now, let's consider the number ab, where a is the tens digit, and b is the unit digit. It follows that
Number=10*a+b
The question gives us two conditions:
1) The sum of a two-digits number is 13.
2) The tens digit is 8 less than twice the units digit.
The first condition can be expressed as:
a + b = 13 [1]
And the second condition can be written as:
a = 2b-8 [2]
Replacing [2] into [1], we have:
2b-8 + b = 13
Operating:
3b = 13 + 8
3b = 21
Solving for b:
b = 21 / 3 = 7
Substituting into [2]:
a = 2*(7) - 8 = 6
Thus, the number is 67
Answer:
C. II only
Step-by-step explanation:
Basically all you need do is plug these answers in and if the complete the inequality to make a true statement.
Yes i know no body want to do that but that whats need to be done lol.
once i plug 7 12/7+8 = 12.83
12.83>20
is incorrect
so we need continue
7*2.5+8>20
7*2.5= 17.5
17.5+8= 25.5
25.5>20
this a true statement
so we know 2.5 is an answer
now we need plug in -3
7*-3= -21
-21 +8 = -13
-13>20
this is incorrect
