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3 years ago

Can anyone explain to me how to solve for this?

Mathematics

1 answer:

il63 [147K]3 years ago

6 0

Answer:

x = 11

Step-by-step explanation:

The angle formed by two secants is half the difference of the intercepted arc angles.

m∠D = ½ (mBS − mCE)

60 = ½ (173 − (5x − 2))

120 = 173 − 5x + 2

5x = 55

x = 11

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2 years ago

PLEASE HELP ASAP <br>are f(x)=4/x-2-1 and g(x)=3/x+2-2 inverses of each other?

GREYUIT [131]

Answer:

To find the inverse of:

$f (x)=\dfrac{4}{x-2}-1$

Set the function to y:

$\implies y=\dfrac{4}{x-2}-1$

Rearrange to make x the subject:

$\implies y+1=\dfrac{4}{x-2}$

$\implies (y+1)(x-2)=4$

$\implies xy-2y+x-2=4$

$\implies xy+x=2y+6$

$\implies x(y+1)=2y+6$

$\implies x=\dfrac{2y+6}{y+1}$

Swap x and y:

$\implies y=\dfrac{2x+6}{x+1}$

Change y to the inverse of the function sign:

$\implies f$ $\:^{-1}(x)=\dfrac{2x+6}{x+1}$

Rewrite g(x) as a fraction:

$g(x)=\dfrac{3}{x+2}-2$

$\implies g(x)=\dfrac{3}{x+2}-\dfrac{2(x+2)}{x+2}$

$\implies g(x)=\dfrac{3-2(x+2)}{x+2}$

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1 year ago

Compare and Contrast how you would factor x^2−9 and x^2+9. For full credit, make sure you explain why they are factored differen

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Quadratic equations are equations with a degree of 2.

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$=x^2-9\\=x^2-3^2$

Using the difference of two squares:

$a^2-b^2=(a-b)(a+b)\\x^2-3^2=(x-3)(x+3)$

For the expression x^2 + 9

The expression x^2 + 9 has no real roots hence cannot be factored

Learn more on factorization here: brainly.com/question/20293447

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2 years ago

Use the distributive property to rewrite 2(8+x) then simplify

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16+2x

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3 years ago

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3 years ago