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Sergio039 [100]
3 years ago
8

Find the third side in simplest radical form

Mathematics
1 answer:
otez555 [7]3 years ago
8 0

Answer:

x= 2\sqrt{6}

Step-by-step explanation:

To solve this problem we first observe the Pythagoras equation. If a=x and b = 7 are the lengths of the legs of a right triangle and c= \sqrt{73} is the length of the hypotenuse, then<u> the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse. </u>

This relationship is represented by the formula:

a*a + b*b = c*c

x^{2} + 7^{2} = (\sqrt{73} )^2

=> x= 2\sqrt{6}

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maks197457 [2]
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5 is in the middle
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3 years ago
Find the surface area of the square pyramid below.
sleet_krkn [62]

Answer:

\displaystyle 762,96\:m.^2 ≈ S.A.

Step-by-step explanation:

\displaystyle a^2 + 2a\sqrt{\frac{a^2}{4} + h^2} = S.A. \\ \\  14^2 + 2[14]\sqrt{\frac{14^2}{4} + 19^2} = S.A. \\ \\ 196 + 28\sqrt{\frac{196}{4} + 361} ≈ 762,9567885 ≈ 762,96

I am joyous to assist you anytime.

7 0
3 years ago
Read 2 more answers
1 What is the solution to the system of equations? (2 Points) x + y = 8 and - x + 3y = 4 O a. (-2, 10) O b. (10,-2) c. (3,5) O d
beks73 [17]

Answer:

(5 , 3)

Step-by-step explanation:

x + y = 8 ----------------(I)

-x + 3y = 4 ----------(II)

Add equation (I) and (II) and so x will be eliminated and we can find the value of y

(I)      x + y    = 8

(II)   -<u>x   + 3y = 4  </u>

             4y = 12  {Divide both sides by 4}

y = 12/4

y = 3

Plugin y = 3 inn equation (I)

x + 3 = 8 {Subtract 3 from both sides}

     x = 8 -3

x = 5

6 0
3 years ago
This picture shows a cube and its net
fenix001 [56]

The formula is 6 a^2

6 x (11^2)

11 x 11=121

6 x 121 = 726

So 726 is your answer

5 0
4 years ago
Read 2 more answers
Entomologists have discovered that a linear relationship exists between the rate of chirping of crickets of a certain species an
vekshin1

Answer:

a) y=4x-160

b) y=4(102)-160=248\frac{chirps}{min}

Step-by-step explanation:

We know that theres a <u><em>linear relationship</em></u> between the rate of the chirping of crickets and the air temperature.

<u><em>The equation of a line is</em></u>:

y=mx+b

So, let's name our variables

x= Temperature

y=Rate of the chirping

First of all, we need to find the <u><em>slope</em></u> with the two given points

x_{1}=60ºF , y_{1} =80\frac{chirps}{min}

x_{2} =80ºF, y_{2} =160\frac{chirps}{min}

By,

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  } =\frac{160-80}{80-60}

m=4

<u>Now, the </u><em><u>equation</u></em><u> between the air temperature and the number of chirps is:</u>

y-y_{1} =m(x-x_{1} )

y-80=4(x-60)

Solving for y,

a) y=4x-160

b) <u>To calculate the </u><u>rate</u><u> at which the crickets chirp when the </u><u>temperature is 102 ºF</u><u> we need to evaluate y(102)</u>

y=4(102)-160=248\frac{chirps}{min}

5 0
3 years ago
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