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3 years ago

H (x)=x^2+ 8x+7 , what function family does this equation belong to?

Mathematics

2 answers:

Citrus2011 [14]3 years ago

8 0

Answer:

Step-by-step explanation:

you could use math papa to help you

Semenov [28]3 years ago

6 0

Answer:

Algebra

Step-by-step explanation:

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5. A stove has a list price of $1,400. If the chain discount is 13/10/4, what's the net price? Also, what's

Arada [10]

Answer:

I think this is the answer. I tried.

Step-by-step explanation:

13/10/4 = .325

A. 1,400 x .325=455

Net Price=1,400-455 = 945

B. Trade Discount = 32.5%

6 0

3 years ago

4^2 x 2<br> Please will give brainliests

vitfil [10]

4^2 = 16
16 x 2 = 32
32, Hope this helps!

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2 years ago

Read 2 more answers

A grocer has two kinds of tea: one selling for 80 cents a pound and the other selling for 60 cents a pound. How many pounds of e

goblinko [34]

Answer:

35 pounds of tea for 80 cents.

Step-by-step explanation:

Equation::

value + value = value

80x + 60(50-x) = 74*50

80x + 60*50 - 60x = 74*50

20x = 14*50

x = 35 lbs (amt. of 80 cent tea to use)

50-x = 15 lbs (amt. of 60 cent tean to use)

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2 years ago

Read 2 more answers

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

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3 years ago

look at this equation and the steps used to solve it. Which answer is the best justification for step 1 of this solution

Julli [10]

Answer:

Step-by-step explanation:

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3 years ago