Answer:
A and C are correct
Step-by-step explanation:
Making the decimal value greater than 4.3 or 4.30 will make the statement correct
Answer: the maximum is 25.
Step-by-step explanation: a max/min can occur on the endpoints of a function and critical points of the function's derivative.
f(x)=x^4-x^2+13
f'(x)=4x^3-2x
The critical points of f'(x) occur when f'(x) is zero or undefined. f'(x) is not ever undefined in this case, so we just need to find the x values for when it's zero.
0=4x^3-2x
x=.707, -.707
Now that we have the critical points of f'(x) (.707 and -.707) and endpoints (-1 and 2), we can plug in these x values into the original function to determine its maximum. When you do this you'll find that the greatest y value produced occurs when x=2 and results in a max of 25.
Answer: 61 unit^2
Step-by-step explanation:
ABCD is a rectangle with dimensions 12 by 11, for a total area of 132 (square units). Although I could determine the lengths of the parallel lines of the interior trapezoid from the data supplied, I'm lazy and decided, instead, to subtract from the total rectangle area the areas of the four right triangles formed outside the shaded area. The area of each triangle is (1/2)b*h, and we are given those dimensions on the figure.
The four triangle areas:
TriD = 36
TriA = 6
TriB = 20
TriC = 9
Total area = 71 square units.
Subtract this from the rectangle's area: 132 - 71 = 61 units^2
This is the area of the shaded trapezoid.
Answer:
Step-by-step explanation:
The question is asking you to graph the equations.
The equations are in slope intercept form so y=mx+b
M is the slope and b is the y-intercept
First draw the y & x axis and label/number them
The y-intercept for the first equation is -1 so draw a dot on the -1 on the y-axis
The slope is 2/5 and you use rise/run to continue the slope.
you rise 2 on the y-axis and go right 5 times on the x-axis (for a negative number you go left/down)
For the second equation, you have to turn it into slope intercept form.
You should get y=2/3x+3
You graph this equation the same as you did the first one.