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3 years ago

(-8, -2) and (1, 9) find the slope

Mathematics

1 answer:

sergejj [24]3 years ago

6 0

Answer:

11/9

Step-by-step explanation:

To find the slope

m = ( y2-y1)/(x2-x1)

= ( 9 - -2)/(1 - -8)

= ( 9+2)/ (1+8)

= 11/9

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Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima

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Answer:

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Step-by-step explanation:

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3 years ago

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

charle [14.2K]

ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

$(f \circ \: g)(x)= \frac{ - 14x}{ - 14} = x$

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3 years ago

Write an expression that can be used in over a temperature from degrees Celsius see to degrees Fahrenheit and then use the expre

densk [106]

Answer:

25°C = 77 degree Fahrenheit.

Step-by-step explanation:

In this question we have to write the expression showing the relation between degree Celsius and degree Fahrenheit first.

$C=\frac{5}{9}(F-32)$ where C = degree centigrade and F = degree Fahrenheit

Although the question is not clear in the next part but assuming that we have to use this expression to convert 25°C to degree Fahrenheit,

We will plug in the value of C in the expression,

$25=\frac{5}{9}(F-32)$

$F=(\frac{9}{5}\times 25)+32$

F = 45 + 32

F = 77

Therefore, 25°C = 77 degree Fahrenheit will be the answer.

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