The school paper charges $1.50 for an ad, plus 25 cents per word. Carl wants to spend only $12.00 on the ad.
2 answers:
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#4) From the reference angle of 58° we can see that we have the side opposite to that angle as well as the hypotenuse. Recall that sin=opp/hyp so we are going to use sine to find that side
sin(58°) =
(multiply both sides by 19 to isolate x)
19 sin(58°) = x (plug into calculator)
16.1 = x
#5) From the reference angle of 56°, we see that we have the adjacent and the opposite sides. Remember that tan=opp/adj so we will use tangent to find x
tan(56°) =
(multiply both sides by 
)
(flip them so x is on the top)
[tex] \frac{12}{tan(56)} = x
8.1 = x
sin(58°) =
19 sin(58°) = x (plug into calculator)
16.1 = x
#5) From the reference angle of 56°, we see that we have the adjacent and the opposite sides. Remember that tan=opp/adj so we will use tangent to find x
tan(56°) =
[tex] \frac{12}{tan(56)} = x
8.1 = x
Answer :
-1/3
Explaination :
K(x) = 3/2x - 1
K(x) = -4
K(-4) = 3 / 2(-4) - 1
K = 3 / -8 - 1
K = 3 / -9
K =