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3 years ago

What is the mean for the following set of data?

Mathematics

2 answers:

Andru [333]3 years ago

7 0

The mean of a data set is equal to the sum of the set of numbers divided by how many numbers are in the set.

So, start by adding the numbers to get 54.

54 will be divided by the number of numbers in the set, or 6.

54 divided by 6 is 9.

So the mean of this data set is 9.

Softa [21]3 years ago

3 0

Answer:

Step-by-step explanation:

5,7,8,10,12,12

5+7+8+10+12+12=54

54/(how many numbers there are, which is 6)=9.

Your mean value is 9.

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Due to a packaging error, 4 cans labeled diet soda were accidentally filled with regular soda and placed in a 12 pack carton of

Sophie [7]

Answer:

Probability that both cans were regular soda = $\frac{1}{11}$

Step-by-step explanation:

Probability = $\frac{Desired outcome}{Total possible outcomes}$

We are given 12 total number of cans; 4 cans have been accidentally filled with diet soda.

Probability that first can is a regular soda:

Outcome that first can is a regular soda will give us the number of regular soda available which are 4

Using formula of probability

Total possible outcomes are, n(total) = 12

Desired outcome: 4 (cans of regular soda)

P(1st can) = $\frac{4}{12}$ = $\frac{1}{3}$

Probability that 2nd can is a regular soda:

As we have already taken a can of regular soda from the pack, the total soda in the pack now 11 and the regular soda left are 3.

Total possible outcomes are, n(total) = 11

Desired outcome: 3 (cans of regular soda as one has already been taken)

P(2nd can) = $\frac{3}{11}$

Probability that both cans are regular soda:

P(both) = P(1st can) × P(2nd can)

= $\frac{1}{3} * \frac{3}{11}$

= $\frac{1}{11}$

3 0

3 years ago

Read 2 more answers

Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0

3 years ago

You are shopping at a department store and all items currently are being sold at full price. You discover that next week the dep

MAVERICK [17]

Answer:

$10.45

Step-by-step explanation:

You need to add up the total price before the sale and after then subtract

18.95 + 7.99 = $26.94

8.99 + 7.50 = $16.49

26.94 - 16.49 = $10.45

4 0

3 years ago

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(-9x - 4) - (4x2 + 2x - 7)

yaroslaw [1]

Answer:

I assume you meant 4x^2

So the answer in simplified form is -4x^2-11x+3

6 0

3 years ago

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Write 0.735 as a simplified fraction

Arisa [49]

Answer:

73/5

Step-by-step explanation:

8 0

3 years ago

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