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2 years ago

Find the greatest common factor of these three expressions.

1 answer:

3 0

6x

42/6 = 7 (valid), 18/6 = 3 (valid), 12/6 = 2 (valid)

7, 8, 9, 10, and 11 are all not divisible by 12, and 12 is not divisible by 18, so 6 is the highest number.

Also, each number has at least one x, so you can take one out.

Remaining=
6x (7 + 3x^2 + 2x^3)

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Enter numbers to write 0.000328

Makovka662 [10]

Answer:

3.28 x 10^-4

Step-by-step explanation:

0.000328 = 3.28 x 10^-4

7 0

2 years ago

Use the GCF to find a new sum for 54+48.<br> _ ( _ + _ )

Maru [420]

Answer: GCF is 6

Step-by-step explanation:

Sort them out on paper

5 0

2 years ago

What is the solutions to the equation w/2w-3=4/w

labwork [276]

Answer:

{2, 6}

Step-by-step explanation:

w/2w-3=4/w is ambiguous. Did you mean

w 4

---------- = ------ ? If so, please enclose "2w - 3" inside parentheses.

2w - 3 w

Cross multiplying, we get w² = 8w - 12.

Putting this into standard form, we get:

w² - 8w + 12 = 0, which factors into (w - 2)(w - 6) = 0.

The solutions are found by setting each factor = 0 separately and solving the resulting equations for w: {2, 6}.

7 0

2 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$

3 0

1 year ago

3. A kite is aloft at the end of a 1500 foot string. The string make an angle of 43° with the

sineoko [7]

Answer:

$h= 1500\,*\,sin(43^o)$

Step-by-step explanation:

Notice that there is a right angle triangle formed with sides as follows:

hypotenuse is the actual 1500 ft string. The acute angle 43 degrees is opposite to the segment that represents the height of the kite from the ground. Therefore, the trigonometric ratio that we can use to find that opposite side to the given angle, is the sine function as shown below:

$sin(43^o) = \frac{opposite}{hypotenuse} \\sin(43^o) = \frac{opposite}{1500}\\opposite = 1500\,*\,sin(43^o)\\h= 1500\,*\,sin(43^o)$

8 0

2 years ago