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Effectus [21]
2 years ago
10

Determine if the set of numbers create a Pythagorean triple. 2.1, 7.2, and 7.5

Mathematics
1 answer:
Minchanka [31]2 years ago
8 0

Answer:

Yes, the set of numbers create a Pythagorean triple

Step-by-step explanation:

we know that

If a set of numbers create a Pythagorean triple, then the set of numbers must satisfy the Pythagorean Theorem

c^2=a^2+b^2

where

c is the greater side

a and b are the legs (perpendicular sides)

we have

c=7.5\\a=2.1\\b=7.2

substitute

7.5^2=2.1^2+7.2^2

56.25=4.41+51.84

56.25=56.25 ----> is true

therefore

Yes, the set of numbers create a Pythagorean triple

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<span> 2 square root of 7 − square root of 28
= 2</span>√7 - √28
= 2√7 - 2√7
= 0
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Select the correct answer.
Anit [1.1K]

Answer:

  D.  I and IV

Step-by-step explanation:

"Discrete" means the quantities can only assume specific (usually integer) values. It is contrasted with "continuous," which describes quantities that can assume any value in some range, not necessarily an integer value.*

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2 years ago
Multiply. (9.42×108)⋅250,000 Enter your answer, in scientific notation, in the box.
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Micah is writing a function that models the height a dolphin reaches when it propels itself from underwater to the surface, leap
stepladder [879]

Answer:

The dolphin will be above the surface of the water for 2 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

The height of the dolphin after t seconds is given by:

h(t) = -16t^2 + 96t - 128

According to Micha's model, how long will the dolphin be above the surface of the water?

It stays above the surface of the water between the first and the second root. Initially, it is below water, when the first time for which h(t) = 0 it crosses the surface upwards, and then the second time for which h(t) = 0 it crosses the surface downwards.

We have to find these roots. So

h(t) = -16t^2 + 96t - 128

-16t^2 + 96t - 128 = 0

Multiplying by -16

t^2 - 6t + 8 = 0

\Delta = (-6)^{2} - 4*1*8 = 36 - 32 = 4

t_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4

t_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2

4 - 2 = 2

The dolphin will be above the surface of the water for 2 seconds.

4 0
2 years ago
What is the value of x in the equation Negative StartFraction 2 over 9 EndFraction x = two-fifths? Negative 1 and four-fifths Ne
pogonyaev

Answer:

Option Negative 1 and four-fifths is correct

That is x=-1\frac{1}{5}

Step-by-step explanation:

Given problem is Negative start fraction 2 over 9 end fraction x=two-fifths

Given equation  can be written as -\frac{2}{9}x=\frac{2}{5}

To find the value of x in the given equation :

-\frac{2}{9}x=\frac{2}{5}

Mutliply by \frac{9}{2} on both sides we have

\frac{2x}{9}\times(\frac{9}{2})=\frac{2}{5}\times(\frac{9}{2})

-x=\frac{9}{5}

x=\frac{-9}{5}

x=-1\frac{1}{5}

therefore the value of x is -1\frac{1}{5}

Option Negative 1 and four-fifths is correct

That is x=-1\frac{1}{5}

3 0
3 years ago
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